<span><span>There are choices for this question namely:
A. Its photons have the shortest wavelength in the visual spectrum
B. Its photons have the highest energy in the visual spectrum
C. Its photons have the longest wavelength in the visual spectrum
D. It is not considered a part of the visual spectrum
The correct answer is that </span>its photons have the longest wavelength in the visual spectrum<span>. Chlorophyll, being green in color (around 495 to 590 nm wavelength), reflects this wavelength; not absorbed. Mostly, the chlorophyll absorbs longer wavelengths of light such as red (around 680 nm wavelength) and blue to violet (around 400 to 480 nm wavelnegth). </span></span>
Given what we know, we can confirm that the biome is in fact an open system due to the interactions between the biosphere, atmosphere, lithosphere, and hydrosphere.
<h3>What is the biome?</h3>
- The biome is the collection of air, soil, water, and all the organisms that reside within these ecosystems.
- In order to describe an open system, we say that the system must have external interactions.
- A biome is an open system because it has both internal and external interactions, such as with asteroids in space.
- The internal interactions include the ones between the<em><u> biosphere, atmosphere, lithosphere, and hydrosphere.</u></em>
- A prime example is the movement of water through each of the spheres.
Therefore, since each part of the biome interacts with each other as well as with external sources such as space, we can confirm that it complies with the definition of an open system.
To learn more about open systems visit:
brainly.com/question/8987993?referrer=searchResults
Answer:
50%
Explanation:
Glucose is a simple sugar with a total of 6 carbon atoms in its structure. Pyruvate has a total of three carbon atoms. Two molecules of pyruvate are obtained per glucose by glycolysis. None of the carbon of glucose is released in the form of CO2 during glycolysis. Therefore, the radio-labeled C-1 of glucose will be the component of the carbon skeleton of one of the total of two pyruvate molecules produced during glycolysis. So, 50% of the pyruvate will exhibit radioactivity.
