Answer:
force exerted by the cat is 693 N
Explanation:
We know that total energy is the sum of work done by gravity and friction i.e.
solving for F
here -ve sign indicate work done in opposite direction
where, m is mass of cat = 4.00 kg
h = 2.00 m,
Putting all value in above equation
F = 692.53 N = 693 N
Therefore force exerted by the cat is 693 N
Answer:
Option (c) is correct.
Explanation:
The apparent change in the frequency of light due to the relative motion between the source and the observer is called Doppler's effect.
When the source is moving towards the observer which is at rest, the apparent frequency increases and if the observer is moving away the frequency of sound decreases.
It occurs for both light and sound.
So, to explain the blue shift of light in the universe is due to the Doppler's effect of light.
A ball at rest hit by a golf club has initial velocity zero. The ball will be moving after the impact at speed of 1.4 x 10⁵ m/s.
<h3>What is force?</h3>
The action of push or pull which changes the state of motion or rest of a body is called force.
The club applies a force of 700N to the ball and the time of impact is 0.05s. The mass of ball is 0.10kg.
The impact force F is equal to the change in momentum of the ball multiplied by time of impact t. The momentum is the product of mass m and velocity v after impact.
F= (mv -mu) x t
The ball is initially at rest, so u =0
F = mvt
Substitute the values into the above equation of force to find the velocity.
v = F / mt
v =700 / (0.10 x 0.05)
v = 1.4 x 10⁵ m/s
Thus, the ball will be moving after the impact at speed of 1.4 x 10⁵ m/s.
Learn more about force.
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Answer:2538.43 N
Explanation:
Given
Mass of Log=205 kg
Ramp angle
Coefficient of Friction=0.855
log acceleration
Let T be the Tension
Here
T=849.04+132.63+1556.76=2538.435 N