Answer:
Q = 1.52 X 10⁻⁷ C.
Explanation:
String is inclined at 10 degree with the vertical so the vertical component of T will balance the weight and the horizontal component will balance the force of repulsion F.
T Cos 10 = mg
T Sin 10 = F
Tan 10 = F / mg
F = mg Tan 10
= 10⁻³ x 9.8 x .176
= 1.728 x 10⁻³ .
Force of repulsion F = K Q² / R²
Distance between two charges = 2 x 1 x sin 10
= .347 m
1.728 X 10⁻³ = [/tex]
Q² = 2.31 X 10⁻¹⁴
Q = 1.52 X 10⁻⁷ C.
Answer:
d=101 m
Explanation:
The time taken to reach the 202m is given by:
the problem states that the balloonist maintain that altitude for 10.3 seconds more, so:
if the bag falls straight down:
if the bag is affected by the velocity of the wind we need to calculate the time that the bag takes to reach the ground.
the total time would be:
Answer:
the highest possible average flow velocity is 17 m/s
Explanation:
given data
power = 60 W
pressure = 50 Pa
diameter = 30 cm = 0.3 m
to find out
Determine the highest possible average flow velocity in the duct
solution
we will apply here energy balance equation that is
energy in = energy out
power + m(Pv)1 = m (Pv)2
power = mv ( P2 -P1)
power = V ΔP
here P is pressure and V is maximum volume flow rate
put here value and find V
60 = V ( 50)
maximum volume v = 1.2 m³/s
and
maximum average velocity is
Velocity =
here D is diameter and V is volume
so
velocity =
velocity = 17 m/s
so the highest possible average flow velocity is 17 m/s