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3 years ago

Do y’all know the answers to them all the choices are at the drop down box.!!!

Physics

2 answers:

Ugo [173]3 years ago

7 0

I would say the second option

Alborosie3 years ago

4 0

the second option is your answer to what a liquid is

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What is the energy of an object in motion

tensa zangetsu [6.8K]

The answer is kinetic energy

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3 years ago

Read 2 more answers

The four best metallic conductors are: A. gold B. cadmium C. alloys D. copper E. silver F. sodium G. aluminum H. iron I have to

RoseWind [281]

Answer:

Explanation:

I can give you four for certain.

Copper

Gold

Silver

Aluminum

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3 years ago

Zina [86]

Answer:

The current through the wire is equal to 0.8 A.

Explanation:

Given that,

The length of a copper wire = 2 m

Potential difference = 24 mV

The current through the wire is 0.40 A.

The new potential difference is 48 mV.

We need to find the current through the wire.

As the potential difference is doubled for second wire. So the new current will be :

I' = 2I

= 2 × 0.4

= 0.80 A

So, the current through the wire is equal to 0.8 A.

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3 years ago

A 750 g air-track glider attached to a spring with spring constant 14.0 N/m is sitting at rest on a frictionless air track. A 20

alexandr402 [8]

Answer:

the amplitude of the subsequent oscillations is 0.11 m

the period of the subsequent oscillations is 1.94 s

Explanation:

given Information:

the mass of air-track glider, $m_{1}$ = 750 g = 0.75 kg

spring constant, k = 13.0 N/m

the mass of glider, $m_{2}$ = 200 g = 0.2 kg

the speed of glider, $v_{2}$ = 170 cm/s = 1.7 m/s

the amplitude of the subsequent oscillations is A = 0.11 m

according to mechanical enery equation, we have

$A = \sqrt{\frac{m_{1} +m_{2} }{k} }v_{f}$

where

A is the amplitude and $v_{f}$ is the final speed.

to find $v_{f}$ , we can use momentum conservation lwa, where the initial momentum is equal to the final momentum.

$P_{f} = P_{i}$

$(m_{1} +m_{2} )v_{f} = m_{1} v_{1} +m_{2}v_{2}$

$v_{1}$ = 0, thus

(0.75+0.2) $v_{f}$ = (0.75)(0)+(0.2)(1.7)

0.95 $v_{f}$ = 0.34

$v_{f}$ = 0.36 m/s

Now we can calculate the amplitude

$A = \sqrt{\frac{0.75 +0.2 }{10} }0.36$

A = 0.11 m

the period of the subsequent oscillations is T = 1.94 s

the equation for period is

T = 2π $\sqrt{\frac{m_{1}+m_{2} }{k} }$

T = 2π $\sqrt{\frac{0.75+0.2 }{10} }$

T = 1.94 s

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3 years ago

For any pure substance, the boiling point and melting point will always remain

zmey [24]

For any pure substance, the boiling point and melting point will always remain sharp or distinct. This is because the substance has uniform properties all throughout. Hope this answers the question. Have a nice day. Feel free to ask more questions.

7 0

4 years ago