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Svetlanka [38]
3 years ago
7

A stone is thrown horizontally at 8.0 m/s from a cliff 78.4 m high. How far from the base of the cliff does the stone strike the

ground?
Physics
2 answers:
Sedaia [141]3 years ago
8 0
....................................................................
64 meters
Ivenika [448]3 years ago
4 0
64 meters from the base of the cliff.
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kicyunya [14]

Answer:

how many feet?

Explanation:

6 0
3 years ago
What is the weight of a 2.06 kg text book. show work please
salantis [7]

The weight of anything is (mass) x (gravity in the place where the thing is).

             Gravity on Earth is about 9.8 newtons per kilogram, so on Earth,
             the weight of the book is

                          (2.06 kg) x (9.8 N/kg) = <em>20.19 newtons</em> .


Another way to get around it is:  

               On Earth, 1 kg of mass weighs about 2.205 pounds, so on earth,
               the weight of the book is

                         (2.06 kg) x (2.205 pounds/kg) = <em>4.54 pounds </em>.


7 0
4 years ago
A train is traveling away from you at 120 km/h. it blows its whistle, and you hear a tone of 0.400 kHz. Take the speed of sound
Vaselesa [24]

Answer:B)439.21 Hz

Explanation:

Given

velocity of train v=120 km/h\approx 120\times \frac{5}{18}=33.33 m/s

frequency of train f_a=0.400 kHz\approx 400 Hz

speed of sound c=340 m/s

frequency from Doppler effect can be calculated by

f_a=(\frac{c}{c+v})\cdot f

400=(\frac{340}{340+33.33})\cdot f

400=\frac{340}{373.33}\cdot f

f=400\times 1.098

f=439.21 Hz

5 0
3 years ago
A girl and her bicycle have a total mass of 40 kg. At the top of the hill her speed is 5.0 m/s. The hill is 10 m high and 100 m
Serhud [2]

Answer:

v =   11 m/s   is her final speed

Explanation:

work done by gravity = m g Δh =   40×9.8×10   = 3920 Joules

Work done by friction = - force×distance =   - 20×100   =   - 2000 Joules

[minus sign because friction force is opposite to the direction of motion]

Initial K.E. = (1/2) m u^2 = (1/2) × 40 × 5^2   = 500 Joules

Now, by work energy theorem

Work done = change in kinetic energy.

Final K.E. = initial K.E. + total work =    500 + 3920 - 2000  = 2420 Joules

Now, Final K.E. = (1/2) m v^2  [final speed being v= speed at the bottom]

⇒  2420 = (1/2)×40×v^2

   ⇒  121 = v^ 2

  v =   11 m/s   is her final speed

5 0
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Why are recessive traits not seen even though they are present in the alleles?​
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