Empirical because it is what you need to know the source of knowledge gather by observation or experimentation.
Answer:
The correct answer is option 'd': The frequency decreases and the intensity of the sound decreases.
Explanation:
1) <u>Effect on Frequency </u>
According to Doppler's effect of sound we have
for a source of sound moving away from the observer the relation between the observed and the original frequency is given by

where
c = speed of sound in air
is the velocity of observer of sound
is the velocity of source of sound
is the original frequency of sound
As we see the ratio is less than 1 thus the frequency of sound that the observer receives is less than that of source.
2) <u>Effect on Intensity:</u>
At a distance 'r' from source emitting a wave of Power 'P' is given by

As we see on increasing 'r' intensity of sound decreases.
Answer:
Force on the singly charged ion will be
Explanation:
We have given electric field E = 8 MN/C
So electric field in N/C will be 
It is given that ion so charge on ion will be equal to 
We have to find the electric force on the ion
Electric force is equal to
, here q is charge and E is electric field
So force on the charge will be equal to 
So force on the singly charged ion will be 
Sum up the moments of the right and the left support:
∑ M2 = 0
F1 · 3.92 m = 46 kg · 9,81 m/s² · 4.46 m + 250 kg · 9.81 m/s² · 1.96 m
F 1 · 3.92 = 2012.6 + 4806.9
F 1 = 6819.5 : 3.92
F 1 = 1739.67 N
∑ M 1 = 0
F 2 · 3.92 m + 46 kg · 9.81 m/s² · 0.54 m = 250 kg · 9.81 m/s² · 1.96 m
F 2 · 3.92 + 243.68 = 4806.9
F 2 · 3.92 = 4563.22
F 2 = 4563.22 : 3.92
F 2 = 1164 N
Answer: The forces on the beam are: F 1 = 1739.67 N and F 2 = 1164 N.