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wolverine [178]

3 years ago

11

Determine the kinetic energy of 1000-kg roller coaster car that is moving with speed of 20.0m/s

1 answer:

nevsk [136]3 years ago

7 0

B, i got the same question

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When water has a temperature greater than 100c, it's boiling

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Which describes a p-type semiconductor?

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It has holes (an electron deficiency).

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Describe the relationship between the potential energy and kinetic energy of an object and the amount of Kinetic energy it can g

ankoles [38]

Kinetic energy of an object is the energy it contains due to movement. If an object is at rest, it doesn't have kinetic energy. If it's moving, then it has kinetic energy. It's pretty simple! The amount of kinetic energy of an object is dependent upon two variables, one being the mass of the object

4 0

3 years ago

An electronic balance shows the mass of a sample of sodium chloride to be 29.732 g. what is the uncertainty of the measurement

OLEGan [10]

The uncertainty of the measurement is 0.001 gm.

The uncertainty in the measurement of a physical quantity is given as how precisely we can measure that, in this case as we can see that the mass of the sodium chloride is precisely given as 29.732 gm, this means the electronic scale is precise to 0.001 gm and round of the values after that which means there is a uncertainty of 0.001 gm.

8 0

3 years ago

A spring has a relaxed length of 35 cm (0.35 m) and its spring stiffness is 12 N/m. You glue a 66 gram block (0.066 kg) to the t

Sonbull [250]

We have that the value for y is

$y=0.12376m$

From the Question we are told that

Relaxed length of 35 cm (0.35 m)

Spring stiffness is 12 N/m.

Glue a 66 gram block (0.066 kg)

Total length is l_t=16 cm

Block during a 0.24-second interval

Generally the equation for the Force of spring of block is mathematically given as

$F_{spring}=kx\\\\\ F_{spring}=12*(0.35-0.16)\\\\ F_{spring}=2.28N$

Generally

$F_{elastic}=-mg\\\\F_{elastic}=-0.066*9.8\\\\F_{elastic}=-0.6468N$

Generally,Net Force

$F_{net}=F_{spring}-F_{elastic}\\\\F_{net}=2.28N-(-0.6468N)\\\\F_{net}=2.9268N$

Generally,Velocity of block

$V_y=\frac{py}{m}$

Where

$Py= F_{net}*dt\\\\Py= 2.9268*0.08\\\\Py=0.234144$

Therefore

$V_y=\frac{0.234144}{0.066}\\\\V_y=3.547m/s$

Generally the equation for the Velocity of block is mathematically given as

$Vy=\frac{yf-yt}{t-t_0}\\\\y=(3.547(0.08-0))-0.16$

$y=0.12376m$

For more information on this visit

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4 0

3 years ago