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Andrew [12]
3 years ago
10

Why are two balls connected by a spring a good model for two atoms connected by a chemical bond?

Physics
1 answer:
Rasek [7]3 years ago
3 0

Answer:

The three choices are correct where, choice (b) If the atoms are moved farther apart, they experience forces resisting the separation and begin to move toward each other. And for choice (c) If the atoms are pushed closer together, they experience forces resisting the compression and begin to move far away from each other. Choice (a) also correct where a spring exerts forces to bring balls (atoms) closer together and also exerts forces to move balls (atoms) apart.

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Why does air pressure decrease with increasing altitude? (Select all that apply.)
Harrizon [31]

Can't help but add me friend i will give you 25 points!

6 0
3 years ago
A bowling pin is thrown vertically upward such that it rotates as it moves through the air, as shown in the figure. Initially, t
zheka24 [161]

Answer:

Explanation:

In projectile, the formula for calculating the maximum height reached by the pin is expressed as;

H = u²/2g

u is the speed/velocity = 10m/s

g is the acceleration due to gravity = 9.81m/s²

Substitute

H = 10²/2(9.81)

H = 100/19.62

H = 5.097m

Hence the maximum height of the center of mass of the bowling pin is most nearly 5.0m

3 0
3 years ago
An electric lamp consumes 60W at 220 volts. How many dry cells of 1.5 V and internal resistance 1 Ohm are required to glow the l
GenaCL600 [577]

Answer:

1. Number of dry cells of 1.5 V required is 40.

2. Number of internal resistance of 1 ohm required is 807

Explanation:

We'll begin by calculating the resistance. This can be obtained as follow:

Power (P) = 60 W

Voltage (V) = 220 V

Resistance (R) =?

P = V²/R

60 = 220² / R

Cross multiply

60 × R = 220²

60 × R = 48400

Divide both side by 60

R = 48400 / 60

R ≈ 807 Ohm

1. Determination of the number of dry cells of 1.5 V required.

Voltage (V) = 220

Dry Cells = 1.5 V

Number of dry cells (n) =?

n = Voltage / Dry cells

n = 60 / 1.5

n = 40

2. Determination of the number of internal resistance of 1 ohm required.

Resistance (R) = 807 Ohm

Internal resistance (r) = 1 ohm

Number of internal resistance (n) =?

n = R/r

n = 807 / 1

n = 807

SUMMARY:

1. Number of dry cells of 1.5 V required is 40.

2. Number of internal resistance of 1 ohm required is 807

3 0
3 years ago
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Murljashka [212]

Answer:

I love that video it’s so funny!!!

Explanation:

3 0
3 years ago
Read 2 more answers
You are camping with two friends, Joe and Karl. Since all three of you like your privacy, you don't pitch your tents close toget
Lemur [1.5K]

Answer:

Distance between Karl and Joe is 38.467 m

Solution:

Let us assume that you are at origin

Now, as per the question:

Joe's tent is 19 m away from yours in the direction 19.0^{\circ} north of east.

Now,

Using vector notation for Joe's location, we get:

\vec{r_{J}} = 19cos(19.0^{\circ})\hat{i} + 19sin(19.0^{\circ})\hat{j}

\vec{r_{J}} = 17.96\hat{i} + 6.185\hat{j} m

Now,

Karl's tent is 45 m away from yours and is in the direction 39.0^{\circ}south of east, i.e.,  - 39.0^{\circ} from the positive x-axis:

Again,  using vector notation for Karl's location, we get:

\vec{r_{K}} = 45cos(-319.0^{\circ})\hat{i} + 45sin(- 39.0^{\circ})\hat{j}

\vec{r_{K}} = 34.97\hat{i} - 28.32\hat{j} m

Now,  obtain the vector difference between \vec{r_{J}} and \vec{r_{K}}:

\vec{r_{K}} - \vec{r_{J}} = 34.97\hat{i} - 28.32\hat{j} - (17.96\hat{i} + 6.185\hat{j}) m

\vec{d} = \vec{r_{K}} - \vec{r_{J}} = 17.01\hat{i} - 34.51\hat{j} m

Now, the distance between Karl and Joe, d:

|\vec{d}| = |17.01\hat{i} - 34.51\hat{j}|

d = \sqrt{(17.01)^{2} + (34.51)^{2}} m

d = 38.469 m

The distance between Karl's and Joe's tent is:

7 0
3 years ago
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