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3 years ago

The linear expansion of a material depends on which of the following?

Physics

1 answer:

nordsb [41]3 years ago

7 0

Answer:

1. The change in temperature of the material.

2. The length of the material.

3. The type of material.

Explanation:

The term linear expansion is defined as the increase in length of any conductor when there is a change in temperature. The new length of any wire or rod is given by :

$L=L_o(1+\alpha \Delta T)$

$L_o$ is the initial length of the rod

$\alpha$ is the coefficient of linear expansion

$\Delta T$ is the change in temperature

It is clear that the linear expansion of a material depends on :

1. The change in temperature of the material.

2. The length of the material.

3. The type of material.

So, all options are correct.

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•• Al and Bert are jogging side-by-side on a trail in the woods at a speed of 0.75 m/s. Suddenly Al sees the end of the trail 35

kolezko [41]

Consider the motion of Al :

v₀ = initial speed of Al = 0.75 m/s

d = distance to be traveled to reach the end of trail = 35 m

a = acceleration = 0.50 m/s²

t = time of travel

Using the equation

d = v₀ t + (0.5) a t²

inserting the values

35 = (0.75) t + (0.5) (0.50) t²

t = 10.4 sec

So Al reach the end of trail after 10.4 sec

Consider the motion of Bert :

x = distance traveled by Bert when Al reach the end = ?

$v_{b}$ = speed of Bert = 0.75 m/s

t = time of travel = 10.4 sec

Distance traveled by Bert when Al reach the end is given as

x = $v_{b}$ t

x = (0.75) (10.4)

x = 7.8

x' = distance remaining to reach the end of trail for Bert = ?

distance remaining to reach the end of trail for Bert is given as

x' = d - x

x' = 35 - 7.8

x' = 27.2 m

$v_{rel}$ = relative velocity of Al with respect to bert = 0.85 + 0.75 = 1.6 m/s

t' = time to meetup

Time to meetup is given as

t' = x' / $v_{rel}$

t' = 27.2/1.6

t' = 17 sec

L = length of the distance of the two from the end

$v_{AL}$ = speed of AL = 0.85 m/s

t' = time to meetup = 17 sec

length of the distance of the two from the end is given as

L = $v_{AL}$ t'

L = (0.85 (17)

L = 14.45 m

7 0

3 years ago

You are walking down a straight path in a park and notice there is another person walking some distance ahead of you. The distan

sveta [45]

Answer:

18.8m

Explanation:

This implies calculating the relative speed first then find the distance d

relative speed = 2.75- 1.25 = 1.5 m/s

So assume the distance between them to be say d

so, d/1.5= 12.5

d = 18.8m

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3 years ago

How can two objects have different mass and volume yet have the same density?

natta225 [31]

Because one object can have more things in it. I learned it a t school today.

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3 years ago

Given 368172 hours, convert to days.

dezoksy [38]

Answer:

15340.5

Explanation:

368172/24 hours

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3 years ago

An airplane is flying 340 km/hr at 12o east of north. the wind is blowing 40 km/hr at 34o south of east. what is the plane's act

jok3333 [9.3K]

Define an x-y coordinate system such that
The positive x-axis = the eastern direction, with unit vector $\hat{i}$ .
The positive y-axis = the northern direction, with unit vector $\hat{j}$ .

The airplane flies at 340 km/h at 12° east of north. Its velocity vector is
$\vec{v}_{1} = 340(sin(15^{o})\hat{i} + cos(15^{o})\hat{j} ) = 88\hat{i} + 328.4\hat{j}$

The wind blows at 40 km/h in the direction 34° south of east. Its velocity vector is
$\vec{v}_{2} =40(cos(34^{o})\hat{i} - sin(24^{o})]\hat{j}) = 33.1615\hat{i} -22.3677\hat{j})$

The plane's actual velocity is the vector sum of the two velocities. It is
$\vec{v}=\vec{v}_{1}+\vec{v}_{2} = 121.1615\hat{i}+306.0473\hat{j}$

The magnitude of the actual velocity is
v = √(121.1615² + 306.0473²) = 329.158 km/h

The angle that the velocity makes north of east is
tan⁻¹ (306.04733/121.1615) = 21.6°

Answer:
The actual velocity is 329.2 km/h at 21.6° north of east.

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3 years ago