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alexandr402 [8]
3 years ago
11

An object located near the surface of Earth has a weight of a 245 N

Physics
1 answer:
gayaneshka [121]3 years ago
7 0

Answer:

ثر أنواع التربة خصوبة التربحمراء .

ج- السوداء

Explanation:

ggfvbdgbvgbbbfgb

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A severe thunderstorm dumped 2.0 in of rain in 30 min on a town of area 22 km2. what mass of water fell on the town? one cubic m
AlekseyPX
For this case, the first thing you should know is that density is defined as the quotient between mass and volume.
 d = m / v
 We have then for this case that the density is:
 d = 103 Kg / m ^ 3
 The volume is given by:
 V = A * d
 Where
 A: area of the city
 d: height of the rain
 Also, for calculation purposes, you must know the following measure:
 1Km = 1000m
 1 inch = 0.0254 meters
 Calculating the volume we have:
 V = (22 * (1000/1) ^ 2) * (2 * (0.0254 / 1)) = 1117600 m ^ 3
 Then, calculating the mass we have:
 m = d * v
 m = (103) * (1117600) = 115112800 Kg
 Equivalently
 m = 1.15 * 10 ^ 8 Kg
 answer
 mass of water fell on the town was 1.15 * 10 ^ 8 Kg
7 0
3 years ago
Read 2 more answers
If the mass of an object is 10 kg and the
ASHA 777 [7]

Answer:

B. -40 kgm/s is the answer

6 0
3 years ago
__________________ is the process by which sediments get pressed together.
Alekssandra [29.7K]

Answer:

compaction

Explanation:

8 0
3 years ago
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A 15.0 kg fish swimming at 1.10 m/s suddenly gobbles up a 4.50 kg fish that is initially stationary. Ignore any drag effects of
Nana76 [90]

Answer

given.

Mass of big fish = 15 Kg

speed of big fish = 1.10 m/s

mass of the small fish = 4.50 Kg

speed of the fish after eating small fish =?

a) using conservation of momentum

m₁v₁ + m₂v₂ = (m₁+m₂) V

15 x 1.10 + 4.50 x 0 = (15 + 4.5)V

16.5 = 19.5 V

V = 0.846 m/s

b) Kinetic energy before collision

KE_1 = \dfrac{1}{2}m_1v_1^2 + \dfrac{1}{2}m_2v_2^2

KE_1 = \dfrac{1}{2}\times 15 \times 1.1^2 + \dfrac{1}{2}m_2\times 0^2

KE₁ = 9.075 J

Kinetic energy after collision

KE_2= \dfrac{1}{2}(15+4.5)\times 0.846^2

KE₂ = 6.98 J

Change in KE = 6.98 - 9.075 = -2.096 J

hence,

mechanical energy was dissipated during this meal = -2.096 J

5 0
3 years ago
11. All objects gain or release heat at the same rate. *
aleksandrvk [35]

The statement is false.

5 0
3 years ago
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