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3 years ago

An object located near the surface of Earth has a weight of a 245 N

Physics

1 answer:

gayaneshka [121]3 years ago

7 0

Answer:

ثر أنواع التربة خصوبة التربحمراء .

ج- السوداء

Explanation:

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Mr.pointer has as mass of 50kg. his is at the top of a 10m hill. what is his PE

iragen [17]

Answer:

PE=4900J

Hope it helps please mark me as brainliest

Explanation:

P.E=m×g×h

Given m = 50 Kg , h = 10 m.

P.E=50×10×9.8

P.E=50×98=4900J

Hence increase in potential energy is 4900J.

6 0

3 years ago

The electric potential energy stored in the capacitor of a defibrillator is 73 j, and the capacitance is 120 f. what is the pote

pychu [463]

The relationship between electrical potential energy (PE), capacitance (C), and potential difference (V) can be expressed through the equation,

V = PE / C

V is equal to the quotient of potential energy and capacitance.

When we substitute the known values from the item,

V = 73 J/ 120 C

V = 0.61 J/C

Thus, the voltage or potential difference is equal to 0.61 V.

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4 years ago

What horizontal velocity should be given to a ball hanging on a 4.9 m long thread so that it slides to the height of the hanger

igomit [66]

Answer:

13 u2 = 0 – (2 × –2 m/s2 × 6 m) = 24, u = 4.9 m

Explanation:

5 0

3 years ago

1 nanometer is equals to?

netineya [11]

1×10^_19 meters

hope it helps you!!!!!

3 0

4 years ago

Read 2 more answers

A stationary sub uses sonar to send a 1.18x10^3 hertz sound wave through ocean water. The reflected sound wave from the flat oce

vampirchik [111]

Answer:

a) v = 1524.7 m/s

b) T = 8.47*10^-4 s

λ = 1.29 m

Explanation:

a) First, in order to calculate the speed of the sound wave, you take into account that the velocity is constant, then, you use the following formula:

$v=\frac{d}{t}$

d: distance traveled by the sound wave, which is twice the distance to the ocean bottom = 2*324 m = 648 m

t: time that sound wave takes to return to the sub = 0.425

$v=\frac{648m}{0.425s}=1524.7\frac{m}{s}$

hence, the speed of the sound wave is 1524.7 m/s

b) Next, with the value of the velocity of the wave you can calculate the wavelength of the wave, by using the following formula:

$v=\lambda f\\\\\lambda=\frac{v}{f}$

f: frequency = 1.18*10^3 Hz

$\lambda=\frac{1524.7m/s}{1.18*10^3s^{-1}}=1.29m$

And the period is:

$T=\frac{1}{f}=\frac{1}{1.18*10^3s^{-1}}=8.47*10^{-4}s$

hence, the wavelength and period of the sound wave is, respectively, 1.29m and 8.47*10^-4 s

5 0

3 years ago