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alexandr402 [8]
2 years ago
11

An object located near the surface of Earth has a weight of a 245 N

Physics
1 answer:
gayaneshka [121]2 years ago
7 0

Answer:

ثر أنواع التربة خصوبة التربحمراء .

ج- السوداء

Explanation:

ggfvbdgbvgbbbfgb

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A typical adult human has a mass of about 70 kg.
Misha Larkins [42]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
a. <span>FM GmMmr2
</span>= 6.67 x 10-11N.m2kg27 .35 x 1022 kg 70 kg 3.78 x 108 m2 
<span>= 2.40 x 10-3 N

b. </span><span>FE GmEmr2
= 6.67 x 10-11 N.m2kg 25 .97 x 1034 kg (70kg) 6.38 x 106 m2
=685 N 
FMFE 2.40 x 10-3N685 N= 0.0004%</span>
3 0
3 years ago
The Pressure in a liquid acts in ________ direction. The pressure _________ as you go deeper because the ______ of the water abo
ryzh [129]

all directions

increases

more

uptrust

6 0
3 years ago
A wall clock has a second hand 22.0 cmcm long. For related problem-solving tips and strategies, you may want to view a Video Tut
olga55 [171]

Answer:

Explanation:

The tip of the second hand moves on a circular path having radius equal to .22 m . Redial acceleration is given by the expression

ω²R where ω is angular velocity and R is radius of the circular path .

angular velocity of second hand = 2π / T where T is time period of circular motion . For second hand it is 60 s.

ω = 2π / T

= 2π / 60

= .1047

angular acceleration =  .1047² x .22

= 2.41 x 10⁻³ rad / s² .

8 0
2 years ago
The formation of a cell plate is a characteristic of
RUDIKE [14]
The formation of a cell plate is a characteristic of cytokinesis in terrestrial plants.
4 0
3 years ago
An irrigation canal has a rectangular cross section. At one point whare the canal is 16.0 m wide, and the water is 3.8 m deep, t
Irina-Kira [14]

Answer:

The depth of the water at this point is 0.938 m.

Explanation:

Given that,

At one point

Wide= 16.0 m

Deep = 3.8 m

Water flow = 2.8 cm/s

At a second point downstream

Width of canal = 16.5 m

Water flow = 11.0 cm/s

We need to calculate the depth

Using Bernoulli theorem

A_{1}V_{1}=A_{2}V_{2}

Put the value into the formula

16.0\times3.8\times2.8=16.5\times x\times 11.0

x=\dfrac{16.0\times3.8\times2.8}{16.5\times11.0}

x=0.938\ m

Hence,  The depth of the water at this point is 0.938 m.

7 0
3 years ago
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