3 years ago

An object located near the surface of Earth has a weight of a 245 N

Physics

1 answer:

gayaneshka [121]3 years ago

7 0

Answer:

ثر أنواع التربة خصوبة التربحمراء .

ج- السوداء

Explanation:

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the imagine above shows to opposite forces acting on a rolling cart, what can we say is true about affect of the forces on the c

cluponka [151]

Answer:

Here is my answer...

Explanation:

The cart will connect with the opposite force, and then the cart will come to a shuddering stop before moving in the direction of the oposite force.

Hope I helped! :)

7 0

2 years ago

What is the centripetal acceleration of the earth as it travels around the sun when Earth has an orbital radius of 1.5 x 10^11 m

masya89 [10]

Answer: $0.0058 m/s^{2}$

Explanation:

Centripetal acceleration $a_{C}$ is calculated by the following equation:

$a_{C}=\frac{V^{2}}{r}$

Where:

$V=29.7 \frac{km}{h} \frac{1000 m}{1 km}=29700 m/s$ is the Earth's orbital speed

$r=1.5(10)^{11} m$ is the orbital radius

$a_{C}=\frac{(29700 m/s)^{2}}{1.5(10)^{11} m}$

$a_{C}=0.0058 m/s^{2}$

4 0

3 years ago

1 point

Yuliya22 [10]

PE= 3kg x 10N/kg x 10m
= 300J

8 0

3 years ago

A charge of 8.5 × 10–6 C is in an electric field that has a strength of 3.2 × 105 N/C. What is the electric force acting on the

Sonja [21]

2.72 N

Explanation:

Step 1:

From the basic formula in electrostatics

F = E * q

where F = Force due to charges

E = Electric field strength

q = Charge

Step 2:

From the given question

q= $8.5*10^{-6} C$

E = $3.2 * 10^{5} N/C$

F = $8.5 * 10^{-6} * 3.2 * 10^{5} = 2.72$ N

8 0

4 years ago

Superman is supposed to leap tall buildings in a single bound. Suppose that he obeys the normal laws of physics in this feat. Es

lys-0071 [83]

Answer:

31.32 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s²

Let us assume the height of the Disque hall is 50 m

$v^2-u^2=2as\\\Rightarrow -u^2=2as-v^2\\\Rightarrow u=\sqrt{v^2-2as}\\\Rightarrow u=\sqrt{0^2-2\times -9.81\times 50}\\\Rightarrow u=31.32\ m/s$

In order to make the jump Superman's initial velocity must be greater than or equal to 31.32 m/s

6 0

3 years ago