Answer:
Established in 1972 by the McMahon Government, the institute's primary function is research for sustainable use and protection of the marine environment. The Institute investigates topics from broad-scale ecology to microbiology.
I think its between b or c
Answer; Cross training enables your body to recuperate faster from injuries, in some cases because other exercises can directly improve the condition caused by your regular activity. For example, Achilles tendonitis, caused by overuse, can be improved by eccentric strengthening of the calf muscles.Explanation:
Answer:
Approximately
.
Explanation:
The average speed of a vehicle is calculated as:
.
In this question, the total distance is
.
The unit of the speeds in this question is meters per second, while the unit of distance is kilometers. Convert the unit of distance to meters:
.
.
Time required for the first part of this trip:
.
Time required for the second part of this trip:
.
The time required for the entire trip would be approximately
.
Calculate the average speed of this plane:
.
Answer:
K = 1.29eV
Explanation:
In order to calculate the kinetic energy of the proton you first take into account the uncertainty principle, which is given by:
(1)
Δx : uncertainty of position = 2.0pm = 2.0*10^-12m
Δp: uncertainty of momentum = ?
h: Planck's constant = 6.626*10^-34 J.s
You calculate the minimum possible value of Δp from the equation (1):
![\Delta p=\frac{h}{4\pi \Delta x}=\frac{6.626*10^{-34}J.s}{4\pi(2.0*10^{-12}m)}\\\\\Delta p=2.63*10^{-23}kg.\frac{m}{s}](https://tex.z-dn.net/?f=%5CDelta%20p%3D%5Cfrac%7Bh%7D%7B4%5Cpi%20%5CDelta%20x%7D%3D%5Cfrac%7B6.626%2A10%5E%7B-34%7DJ.s%7D%7B4%5Cpi%282.0%2A10%5E%7B-12%7Dm%29%7D%5C%5C%5C%5C%5CDelta%20p%3D2.63%2A10%5E%7B-23%7Dkg.%5Cfrac%7Bm%7D%7Bs%7D)
The minimum kinetic energy is calculated by using the following formula:
(2)
m: mass of the proton = 1.67*10^{-27}kg
![k=\frac{(2.63*10^{-23}kgm/s)^2}{2(1.67*10^{-27}kg)}=2.08*10^{-19}J](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B%282.63%2A10%5E%7B-23%7Dkgm%2Fs%29%5E2%7D%7B2%281.67%2A10%5E%7B-27%7Dkg%29%7D%3D2.08%2A10%5E%7B-19%7DJ)
in eV you have:
![2.08*10^{-19}J*\frac{6.242*10^{18}eV}{1J}=1.29eV](https://tex.z-dn.net/?f=2.08%2A10%5E%7B-19%7DJ%2A%5Cfrac%7B6.242%2A10%5E%7B18%7DeV%7D%7B1J%7D%3D1.29eV)
The kinetic energy of the proton is 1.29eV