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kiruha [24]
3 years ago
15

Given the parent function f(x)= log10^x and g(x)= 5x-2, what is f(x) • g(x)?

Mathematics
1 answer:
olchik [2.2K]3 years ago
6 0

Answer:

5x \log_{10}(x)-2 \log_{10}(x)

(If that closed circle is an open circle, please let me know because that means something totally different)

Step-by-step explanation:

I think you are given:

f(x)=\log_{10}(x) \text{ and } g(x)=5x-2

and that you are asked to find:

f(x) \cdot g(x)

That operation means multiplication. (Let me know if is an open circle because that means something difference).

f(x) \cdot g(x)

(\log_{10}(x) \cdot (5x-2)  

Distribute:

\log_{10}(x)(5x)-\log_{10}(x)(2)

Reorder a little (commutative property):

5x \log_{10}(x)-2 \log_{10}(x)

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taurus [48]
The answer is C hope this helps
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2 years ago
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M is the midpoint of , cm = 2x + 3, and md = 3x – 6. what is cd? answer
wlad13 [49]
<span>If M is the midpoint of CD, CM = 2x+3 and MD = 3x-6, then:

MD = CM
3x - 6 = </span>2x + 3
3x - 2x = 3 + 6
x = 9

CM = 2x+3 = 2*9+3  18+3 = 21
MD = CM = 21
CD = CM + MD = 21 + 21 = 42
7 0
3 years ago
a cone shaped container has a height of 9 inches and a diameter or 2in it is filled with a liquid that is worth $2 per cubic inc
Mice21 [21]

Answer:

$18.84

Step-by-step explanation:

The area of a cone is (1/3)pi*r^2*h

With all variables plugged in we get an area of (1/3)*3.14*(1^2)*9, or 9.42 cubic inches. With a value of 2$/in^3, we get 2*9.42, or 18.84.

Therefore, the value of the container is $18.84.

5 0
3 years ago
Please Help!
Tamiku [17]

Answer:

n

Step-by-step explanation:

the answer is -60, which is not an option

4 0
2 years ago
In the rolling of two fair dice calculate the following: P(Sum of the two dice is 7) = ______
vesna_86 [32]

Answer:

P(Sum of the two dice is 7) = 6/36

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

In this problem, we have that:

A fair dice can have any value between 1 and 6 with equal probability. There are two fair dices, so we have the following possible outcomes.

Possible outcomes

(first rolling, second rolling)

(1,1), (2,1), (3,1), (4,1), (5,1), (6,1)

(1,2), (2,2), (3,2), (4,2), (5,2), (6,2)

(1,3), (2,3), (3,3), (4,3), (5,3), (6,3)

(1,4), (2,4), (3,4), (4,4), (5,4), (6,4)

(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)

(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

There are 36 possible outcomes.

Desired outcomes

Sum is 7, so

(1,6), (6,1), (5,2), (2,5), (3,4), (4,3).

There are 6 desired outcomes, that is, the number of outcomes in which the sum of the two dice is 7.

Answer

P(Sum of the two dice is 7) = 6/36

7 0
3 years ago
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