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polet [3.4K]
3 years ago
11

A 4 kg object possesses 18 J of kinetic energy. What is its velocity?

Physics
1 answer:
Alex Ar [27]3 years ago
8 0

Answer: 3 m/s

Explanation:

Mass of object = 4kg

Velocity = ?

Kinetic energy = 18J

Recall that kinetic energy is the energy possessed by a moving object, and it depends on its mass M and velocity, V

Thus, Kinetic energy = 1/2 x mv^2

18J = 1/2 x 4kg x v^2

18J = 0.5 x 4kg x v^2

18J = 2kg x v^2

v^2 = 18/2

v^2 = 9

v = √9 (square root of 9)

v = 3 m/s

Thus, the velocity is 3m/s

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.2, A car starting from rest has an acceleration of
riadik2000 [5.3K]

Answer: 2.5 m/s and 6.25 m

Explanation:

u = 0

a = 0.5 m/s²

t = 5 s

v = u + at

=  0 + 0.5 × 5

= <u>2.5 m/s</u>

s = ut + 1/2 at²

= 1/2 × 2.5 × 5

=<u> 6.25 m</u>

7 0
4 years ago
Name three characteristics of scientists that are important to their work but are also found in nonscientists.
Alina [70]

Answer:

The three characteristics of a good scientist are his curiosity, creativity and problem-solving skills.

Explanation:

3 0
3 years ago
How much energy will a stock tank heater rated at 1790 Watts use in a 24 hour period? 1. 1790 × 24 × 3600 Joules 2. 1790 × 24 ×
Rashid [163]
<h2>Option 1 is the correct answer.</h2>

Explanation:

Power of heater, P = 1790 W

Time used, t = 24 hours = 24 x 60 x 60 = 24 x 3600 s

We have the equation

               \texttt{Power}=\frac{\texttt{Energy}}{\texttt{Time}}

We need to find energy,

Substituting

                 \texttt{Power}=\frac{\texttt{Energy}}{\texttt{Time}}\\\\1790=\frac{\texttt{Energy}}{24\times 3600}

                  Energy = 1790 x 24 x 3600 J

Option 1 is the correct answer.

3 0
3 years ago
Describe how the smoke particles move when a candle was blown out?​
lukranit [14]

Answer:

When a candle was blown out, the flame stops immediately but the wick and the wax are both still hot, so pyrolysis continues for a few seconds. Explanation:

4 0
3 years ago
A pole AB of length 10.0m and weight 600N has its center of gravity 4.0m from the end A, and lies on horizontal ground .Calculat
postnew [5]

Answer:

The force required to begin to lift the pole from the end 'A' is 240 N

Explanation:

The given parameters for the pole AB are;

The length of the pole, l = 10.0 m

The weight of the pole, W = 600 N ↓

The distance of the center of gravity of the pole from the side 'A' = 4.0 m

Let 'F_A' represent the force required to begin to lift the pole from the end 'A' and let a force applied in the upwards direction be positive

For equilibrium, the sum of moment about the point 'B' = 0, therefore, taking moment about 'B', we have

F_A × 10.0 m - W × 4.0 m = 0

∴ F_A × 10.0 m = W × 4.0 m = 600 N × 4.0 m

F_A × 10.0 m = 600 N × 4.0 m

∴  F_A = 600 N × 4.0 m/(10.0 m) = 240 N

The force required to begin to lift the pole from the end 'A', F_A = 240 N.

8 0
3 years ago
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