Answer:
v₂ = 53.23 m/s
Explanation:
Given that,
The mass of a golf club, m₁ = 158 g = 0.158 kg
The initial speed of a golf club, u₁ = 48.2 m/s
The mass of a golf ball, m₂ = 46 g = 0.046 kg
It was at rest, u₂ = 0
Immediately after the collision, the club head continues to travel in the same direction but at a reduced speed of 32.7 m/s, v₁ = 32.7 m/s
We use the conservation of energy to find the speed of the golf ball just after impact as follows :
So, the speed of the golf ball just after the impact is equal to 53.23 m/s.
Increasing the level of an incline:
Increases final velocity
Increases the work done
Increases the initial potential energy
Increases the final kinetic energy
Answer:
Force applied to stop the softball: - 8 N
See if they are asking for the absolute value of this, which will be 8 N.
Explanation:
In order to apply the formula F = m * a, we need to find the acceleration that is imparted on the ball to change its velocity from 32 m/s to zero m/s.
We use the formula for acceleration:
where the initial velocity is 32 m/s, the final velocity is 0 m/s, and the time (t) it took to make this change is: 0.8 seconds:
where the answer comes on given the units for the velocities and time used.
Then, knowing the mass of the softball, we can calculate the force applied:
So the absolute value of this force (force of impact) is 8 Newtons.
We cannot consider something to be work unless <span>force applied causes movement of an object in the same direction as the applied force. </span>