Which statement best describes John Dalton’s use of creativity in his work?

1 answer:

6 0

<span>The scientist thought that the atom was the smallest particle in the universe is John Dalton. He established the atomic theory which consists of five; elements are made of extremely small particles called atoms, atoms of different element have different sizes, mass and physic – chemical properties, atoms cannot be divided further, destroyed or created, atoms can combine to form compounds and in chemical reaction, atoms can be combined, separated or rearranged</span>

You might be interested in

A lightbulb filled with argon gas has a volume of 75 mL at STP. How many moles of argon gas does the lightbulb contain?

Elan Coil [88]

Answer:

0.00335 moles

Explanation:

From the question, Using

PV = nRT................... Equation 1

Where P = pressure, V = Volume, n = number of moles of argon gas, R = Molar gas constant, T = Temperature.

make n the subject of the equation

n = PV/RT............... Equation 2

Given: P = 1 atm (standard pressure), T = 273 K (standard temperature), V = 75 mL = 0.075 dm³

Constant: R = 0.082 atm·dm³/K·mol

Substitute into equation 2

n = (1×0.075)/(273×0.082)

n = 0.075/22.386

n = 0.00335 moles

4 0

2 years ago

the purpose of the ____ system prevent foreign substances from entering the body and to attack foreign substances that are in th

Ratling [72]

Immune System is the answer.

7 0

3 years ago

Papi munyanyo eeeeeeeeeeeeeeeeeeeeeeeeeeee

xenn [34]

Answer:

YES YES YES YES YES YES YES YES YES YES YES YES

8 0

2 years ago

Read 2 more answers

What is the volume of an oxygen tank if it contains 12 moles of oxygen at 273 K under 75 kPa?

Zina [86]

Given:
n = 12 moles of oxygen
T = 273 K, temperature
p = 75 kPa, pressure

Use the ideal gas law, given by
$pV=nRT \\ or \\ V= \frac{nRT}{p}$
where
V = volume
R = 8.3145 J/(mol-K), the gas constant

Therefore,
$V= \frac{(12\,mol)(8.3145\, \frac{J}{mol-K} )(273\,K)}{75 \times 10^{3} \, Pa}= 0.3632\,m^{3}$

Answer: 0.363 m³

5 0

3 years ago

At 350°c, keq = 1.67 × 10-2 for the reversible reaction 2hi (g) ⇌ h2 (g) + i2 (g). what is the concentration of hi at equilibriu

mariarad [96]

According to the reversible reaction equation:

2Hi(g) ↔ H2(g) + i2(g)

and when Keq is the concentration of the products / the concentration of the reactants.

Keq = [H2][i2]/[Hi]^2

when we have Keq = 1.67 x 10^-2

[H2] = 2.44 x 10^-3

[i2] = 7.18 x 10^-5

so, by substitution:

1.67 x 10^-2 = (2.44 x 10^-3)*(7.18x10^-5)/[Hi]^2

∴[Hi] = 0.0033 M

7 0

3 years ago