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harkovskaia [24]
3 years ago
12

Cube root

e=" - 4 \sqrt[3x]{x + 25 = 35} " alt=" - 4 \sqrt[3x]{x + 25 = 35} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Taya2010 [7]3 years ago
8 0

Answer:

\large\boxed{x=-\dfrac{44,475}{64}}

Step-by-step explanation:

-4\sqrt[3]{x+25}=35\\\\\left(-4\sqrt[3]{x+25}\right)^3=35^3\\\\-4^3(x+25)=42,875\\\\-64(x+25)=42,875\qquad\text{use distributive property}\\\\-64x-1,600=42,875\qquad\text{add 1,600 to both sides}\\\\-64x=44,475\qquad\text{divide both sides by (-64)}\\\\x=-\dfrac{44,475}{64}

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when 6 is subtracted from the square of a number, the result is 5 times the number. Find the negative solution.
sveta [45]

When 6 is subtracted from the square of a number, the result is 5 times the number, then the negative solution is -1

<h3><u>Solution:</u></h3>

Given that when 6 is subtracted from the square of a number, the result is 5 times the number

To find: negative solution

Let "a" be the unknown number

Let us analyse the given sentence

square of a number = a^2

6 is subtracted from the square of a number = a^2 - 6

5 times the number = 5 \times a

<em><u>So we can frame a equation as:</u></em>

6 is subtracted from the square of a number = 5 times the number

a^2 - 6 = 5 \times a\\\\a^2 -6 -5a = 0\\\\a^2 -5a -6 = 0

<em><u>Let us solve the above quadratic equation</u></em>

For a quadratic equation ax^2 + bx + c = 0 where a \neq 0

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Here in this problem,

a^2-5 a-6=0 \text { we have } a=1 \text { and } b=-5 \text { and } c=-6

Substituting the values in above quadratic formula, we get

\begin{array}{l}{a=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(-6)}}{2 \times 1}} \\\\ {a=\frac{5 \pm \sqrt{25+16}}{2}=\frac{5 \pm \sqrt{49}}{2}} \\\\ {a=\frac{5 \pm 7}{2}}\end{array}

We have two solutions for "a"

\begin{array}{l}{a=\frac{5+7}{2} \text { and } a=\frac{5-7}{2}} \\\\ {a=\frac{12}{2} \text { and } a=\frac{-2}{2}}\end{array}

<h3>a = 6 or a = -1</h3>

We have asked negative solution. So a = -1

Thus the negative solution is -1

6 0
3 years ago
Solve 4x+2=12 for using the change of base formula logby=logy over logb
s2008m [1.1K]

Answer:

log₄ 10 = log₁₀ 10 / log₁₀ 4

Step-by-step explanation:

Taking the x to be a power then;

4^x +2 =12

4^x = 12-2

4^x=10

Introduce log on both sides

x log 4= log 10

x= log 10/log 4

log₄ 10 = log₁₀ 10 / log₁₀ 4

8 0
3 years ago
Read 2 more answers
What is the measurement of Angle x. please explain​
ki77a [65]
The measurement of angle x is 40°. these two triangle are congruent so their sides share the same length and their angles share the same degrees
3 0
2 years ago
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What is three squared minus two thirds?
Tems11 [23]

three squared minus two thirds

3^2-\frac{2}{3}

three square = 3 x 3 = 9

\begin{gathered} 3^2-\frac{2}{3}=9-\frac{2}{3} \\ 3^2-\frac{2}{3}=\frac{9}{1}-\frac{2}{3} \end{gathered}

Least common factor of 1 and 3 is 3

\begin{gathered} 3^2-\frac{2}{3}=\frac{9}{1}-\frac{2}{3} \\ 3^2-\frac{2}{3}=\frac{27-2}{3} \\ 3^2-\frac{2}{3}=\frac{25}{3} \end{gathered}

Three squared minus two third is twenty five by three.

5 0
1 year ago
Write an equation of the line that passes through (-4, 1) and is parallel to the
LiRa [457]

Answer:

y-1=2(x+4) or y=2x+9

Step-by-step explanation:

y - 3 = 2(x + 7)

y=mx+b

m=2

(x1,y1) -> (-4, 1)

(y−y1)=m(x−x1)

plug in

y-1=2(x+4)

y-1=2x+8

y=2x+9

test:

(1)=2(-4)+9

1=-8+9

1=1

4 0
2 years ago
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