Answer:
CaCl2
And
potasium phosphate is a general name for salt of potassium and phosphate ions . The compounds can exist as
K3PO4 (Tripotassium phosphate)
K2HPO4 (di potassium phosphate)
KH2PO4 (mono potassium phosphate)
Explanation:
Calcium chloride salt is an ionic compound. so it contains both cations and anions. That means it has a positively charged ion and a negatively charged ion. In an ionic compound their is a transfer of electron. The valence electron or the charge ion present in an atom can be use to predict the chemical formula of this compound . Base on the compound the positive end is calcium while the negative end is chlorine .
Ca2+ and Cl-
cross multiply the charges
CaCl2
The charge of phosphate ions are (PO4)3−, (HPO4)2− and (H2PO4)−. And base on the valence electron potassium has a stable charge of +1 (K+). The phosphate ion produces the negative charge when it reacts with potassium.
If potassium goes into reaction with any of the phosphate ion it will be as follows.
K+ and (PO4)3−
cross multiply the charge as usual
K3PO4(tripotassium phosphate)
K+ and (HPO4)2−
cross multiply the charge as usual
K2HPO4(di potassium phosphate)
K+ and (H2PO4)−
cross multiply the charge as usual
KH2PO4 (mono potassium phosphate)
They are hard solid with a crystal lattice structure... with high melting points
Answer:
Negatively charged ions are called anions, and an anion is formed when an atom gains an electron. Thus, the atom has an extra charge of electrons,
Explanation:
so it becomes negatively charged.
Answer:
k = -0.0525 s⁻¹
Explanation:
The equaiton for a first order reaction is stated below:
ln[A]=−kt+ln[A]₀.
[A] = 5.50 x 10⁻³ M
[A]₀ = 7.60 x 10⁻² M
t = 85.0 - 35.0 = 50.0 s
The rate constant is represented by k and can be calculated substituting the values given above:
k = (ln[A]₀ - ln[A])/t
k = (ln5.50 x 10⁻³ M - ln7.60 x 10⁻² M)/50.0s
k = -0.0525 s⁻¹