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Anna007 [38]
2 years ago
7

Which change to the experimental design would improve the reliability of the engineers' measurements?

Chemistry
1 answer:
luda_lava [24]2 years ago
4 0

Answer:

c

Explanation:

sorry if im wrong my apolgies but i think c cus thats the only one that says equal amounts of something

like to test a drop of each so its balanced

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The creation of carbon monoxide is an effect. What is one cause?
myrzilka [38]
Carbon dioxide can be the cause of burning carbon dioxide and a stove it depends on the heat of the flame in order for carbon dioxide to become carbon monoxide 

sorry hope that helps though 
5 0
3 years ago
(c) Assume you have an equilibrium mixture of [A], [B], and [C] at 298K and that the
djyliett [7]

Answer:

Explanation:

1. The amount of CaCO3 must be so small that  

P

CO

2

 is less than KP when the CaCO3 has completely decomposed. In other words, the starting amount of CaCO3 cannot completely generate the full  

P

CO

2

 required for equilibrium.

3. The change in enthalpy may be used. If the reaction is exothermic, the heat produced can be thought of as a product. If the reaction is endothermic the heat added can be thought of as a reactant. Additional heat would shift an exothermic reaction back to the reactants but would shift an endothermic reaction to the products. Cooling an exothermic reaction causes the reaction to shift toward the product side; cooling an endothermic reaction would cause it to shift to the reactants’ side.

5. No, it is not at equilibrium. Because the system is not confined, products continuously escape from the region of the flame; reactants are also added continuously from the burner and surrounding atmosphere.

7. Add N2; add H2; decrease the container volume; heat the mixture.

9. (a) ΔT increase = shift right, ΔP increase = shift left; (b) ΔT increase = shift right, ΔP increase = no effect; (c) ΔT increase = shift left, ΔP increase = shift left; (d) ΔT increase = shift left, ΔP increase = shift right.

11. (a)  

K

c

=

[

CH

3

OH

]

[

H

2

]

2

[

CO

]

; (b) [H2] increases, [CO] decreases, [CH3OH] increases; (c), [H2] increases, [CO] decreases, [CH3OH] decreases; (d), [H2] increases, [CO] increases, [CH3OH] increases; (e), [H2] increases, [CO] increases, [CH3OH] decreases; (f), no changes.

13. (a)  

K

c

=

[

CO

]

[

H

2

]

[

H

2

O

]

; (b) [H2O] no change, [CO] no change, [H2] no change; (c) [H2O] decreases, [CO] decreases, [H2] decreases; (d) [H2O] increases, [CO] increases, [H2] decreases; (f) [H2O] decreases, [CO] increases, [H2] increases. In (b), (c), (d), and (e), the mass of carbon will change, but its concentration (activity) will not change.

15. Only (b)

17. Add NaCl or some other salt that produces Cl− to the solution. Cooling the solution forces the equilibrium to the right, precipitating more AgCl(s).

19. (a)

Hope this helps :)

3 0
3 years ago
Please help answering 11)
8090 [49]

Answer:

the answer is C

Explanation:

8 0
3 years ago
8. What is the % weight of Nickel in Nickel Sulfamate (Ni(SO3NH2)2) ?​
uranmaximum [27]

Answer:

% weight of nickle = 24 %

Explanation:

molar mass of Nickel Sulfamate (Ni(SO₃NH₂)₂) = 250.87 g/mol

Solution

1st we write down the molar mass of Ni

molar mass of Ni = 59 g/mol

now we write down the number of moles of Ni in (Ni(SO₃NH₂)₂)

number of moles of Ni = 1 mol

Now we calculate the mass of nickle present in (Ni(SO₃NH₂)₂)

<em>         mass = moles × molar mass</em>

mass = 1 mol × 59 g/mol

mass = 59 g

now we calculate the % weight of nickle in (Ni(SO₃NH₂)₂)

<em>       % weight = (weight of element ÷ total weight) × 100</em>

% weight of nickle = (59 ÷ 250.87) × 100

% weight of nickle = 0.24 × 100

% weight of nickle = 24 %

7 0
3 years ago
A solution was indicated to have a pH value of 3.52. What is the (H+) of this solution?
san4es73 [151]

Answer:

A pH less than 7 indicates an acidic solution and a pH greater than 7 indicates a basic solution. Ultimately, the pH value indicates how much H+ has dissociated from molecules within a solution. The lower the pH value, the higher concentration of H+ ions in the solution and the stronger the acid.

Explanation:

N/A

3 0
3 years ago
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