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zvonat [6]
2 years ago
9

The fuel used in many disposable lighters is liquid butane, C4H10. Butane has a molecular weight of 58.1 grams in one mole. How

many carbon atoms are in 2.50 g of butane?
Chemistry
2 answers:
Dennis_Churaev [7]2 years ago
6 0
The first thing you need to do is calculate the molar mass of C4H10. To do this, look at a periodic table for the atomic mass of carbon and hydrogen. For Hydrogen it's 1.008 amu. For Carbon its 12.01 amu. This means that a mole of hydrogen has a mass of 1.008 amu. So to calculate the molar mass of C4H10:

atomic mass of H * number of H atoms in one molecule + atomic mass of C * number of C atoms in one molecule
1.008 * 10 + 4 * 12.01
= 58.12 g

So one mole of C4H10 would have a mass of 58.12 g.

Now you were told to find the number of moles for 2.50 g, so you need to change 2.50g into moles

2.50g *1 mole/ 58.12 g = .043014 moles of C4H10

You know that for every mole of C4H10, there are 4 moles of Carbon

so
.043014 mole C4H10 * 4 mole C/1 mole C4H10 = .172 mol C
Now to find the number of atoms, use avogadros numbe5r

6.022 * 10^23 * .17 mol = 1.024 × 10^23 atoms your answer.The first thing you need to do is calculate the molar mass of C4H10. To do this, look at a periodic table for the atomic mass of carbon and hydrogen. For Hydrogen it's 1.008 amu. For Carbon its 12.01 amu. This means that a mole of hydrogen has a mass of 1.008 amu. So to calculate the molar mass of C4H10:

atomic mass of H * number of H atoms in one molecule + atomic mass of C * number of C atoms in one molecule
1.008 * 10 + 4 * 12.01
= 58.12 g

So one mole of C4H10 would have a mass of 58.12 g.

Now you were told to find the number of moles for 2.50 g, so you need to change 2.50g into moles

2.50g *1 mole/ 58.12 g = .043014 moles of C4H10

You know that for every mole of C4H10, there are 4 moles of Carbon

so
.043014 mole C4H10 * 4 mole C/1 mole C4H10 = .172 mol C
Now to find the number of atoms, use avogadros numbe5r

6.022 * 10^23 * .17 mol = 1.024 × 10^23 atoms your answer.

Hope it helps
wel2 years ago
3 0

Answer:

Do you have 1,04 ×10²³ carbon atoms in 2,50g of butane.

Explanation:

  • With molecular weight you can know how many moles do you have from a quantity of grams:

2,50 g  ₓ ( 1 mol butane / 58,1 g ) = 0,043 moles of butane

  • With moles and Avogadro number you can obtain the number of molecules, in this case, of butane:

0,043 moles of butane × ( 6,022×10²³ molecules / 1 mol ) =

2,59 ×10²² molecules of butane

  • Knowing a molecule of butane has four carbon atoms ( molecular formula of butane is C₄H₁₀) you can obtain the number of carbon atoms:

2,59 ₓ 10 ²² molecules of butane ( 4 carbon atoms / 1 molecule of butane ) =

1,04 ×10²³ carbon atoms

I hope it helps!

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Yanka [14]

Answer:

E) None of the above

Explanation:

Metals react according to the activity series, thta is organized with the leats metals in in the bottom and the most reactive metals in the top. Most reactive metals displace less reactive metals in the compounds they are found.

in this series, Gold, Silver and Mercury are below Copper, this is, they are less reactive than Cu. this means none of them can displace it from its compounds.

4 0
3 years ago
Tim wants to store 0.122 moles of helium gas at 203 kPa and 401 K. Which is the volume of the helium gas needed for storage?
algol13

 The  volume  of Helium gas needed for storage  is 2.00 L (answer C)


 <u><em> calculation</em></u>

 The volume of Helium is calculated using ideal gas equation

That is Pv =nRT

where;

 P( pressure) = 203 KPa

V(volume)=?

n(number  of moles) =  0.122 moles

R(gas constant) = 8.314  L.Kpa/mol.K

T(temperature)= 401 K

make V the  subject of the formula  by diving both side  by P

V=nRT/p

V={[0.122  moles x 8.314 L. KPa/mol.K  x 401 K]  / 203 KPa} = 2.00 L


3 0
3 years ago
I need help with with number 1515. How many moles of NO2 are in a 37.058 L container at 101.28 kPa and -139.86
Andre45 [30]

Explanation:

To solve this question, we will use the Clayperon Equation:

P.V = n.R.T

where:

P = 101.28 kPa

1 atm = 101,325 Pa

x atm = 101,280 Pa

x = 1 atm

V = 37.058 L

n = we don't know

R = 0.082 atm.L/K.mol

T = -139.88 ºC = -139.88+273.15 = 133.27 K

1*37.058 = n*0.082*133.27

n = 0.29 moles

Answer: 0.29 moles

5 0
10 months ago
2c+02=2CO2. The moles of co2 produced when 0.25 moles of O2 react is?​
Sophie [7]
<h3>Answer:</h3>

\displaystyle 0.5 \ mol \ CO_2

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Moles
  • Compounds

<u>Stoichiometry</u>

  • Using Dimensional Analysis
  • Analyzing Reactions RxN
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] 2C + O₂ → 2CO₂

[Given] 0.25 moles O₂

[Solve] moles CO₂

<u>Step 2: Identify Conversions</u>

[RxN] 1 mol O₂ → 2 mol CO₂

<u>Step 3: Stoichiometry</u>

  1. [DA] Set up:                                                                                                     \displaystyle 0.25 \ moles \ O_2(\frac{2 \ mol \ CO_2}{1 \ mol \ O_2})
  2. [DA] Multiply/Divide [Cancel out units]:                                                        \displaystyle 0.5 \ mol \ CO_2
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Answer:

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3 years ago
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