Which satellite has the greatest gravitational force with Earth?
2 answers:
Answer: Option 4, the satellite D.
Explanation: The gravitational force between two objects is given by the formula:
where m1 and m2 are the masses of the objects, G is a constant, and r is the distance between both objects.
From this equation, you can see that the gravitational force between two objects increments when the masses of the objects increases, and when the distance between the object decreases.
You can see that all the options are at the same distance from the earth, 320km, then the only factor that changes is the mass of the satellite.
And, based on the previous, the satellite with more mass is the satellite that has the greatest gravitational force with the earth, and this would be the satellite D, with amas of 500kg.
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Answer:
The final velocity is
Explanation:
From the question we are told that
The mass of the child is
The initial speed of the child is
The mass of the wagon is
The initial speed of the wagon is
The mass of the ball is
The initial speed off the ball is
Generally the initial speed of the system (i.e the child , wagon , ball) is
Generally from the law of linear momentum conservation
Here is the momentum of the system before the ball is dropped which is mathematically represented as
=>
=>
and
is the momentum of the system after the ball is dropped which is mathematically represented as
=>
So
=>
Answer:
C. Your mass is very small compared to Earth's mass.
Explanation:
Newton's third law of motion states that:
"When an object A exerts a force (action force) on an object B, object B exerts an equal and opposite force (reaction force) on object A".
If we apply this law to the situation described in the problem, we see that:
- The action force is the gravitational force exerted by the Earth on you
- The reaction force is the gravitational force exerted by you on the Earth
And according to the 3rd law, the magnitude of the two forces is equal:
(1)
We also know that, according to Newton's second law of motion, the force on an object is equal to the product between its mass (m) and its acceleration (a):
So we can rewrite (1) as
where
m is the your mass
a is your acceleration
M is the Earth's mass
A is the Earth's acceleration
For the term on the left, we see that m is small, so a is larger (therefore, your acceleration is visible). However, for the term on the right, we see that the mass of the Earth is very large (M is very large), therefore, A is very small, which means that the acceleration of the Earth is almost negligible because the Earth's mass is very large.