Answer:
50 V
Explanation:
The formula electric potential is given as,
V = kq/r............. Equation 1
q = Vr/k ................. Equation 2
Where q = charge at that point, V = Electric potential, k = coulombs constant, r = distant.
Given: V = 100 V, r = 2.0 m, k = 9.0×10⁹ Nm/C².
Substitute into equation 1
q = (100×2)/(9.0×10⁹ )
q = (200/9)(10⁹)
q = 22.22×10⁻⁹
q = 2.22×10⁻⁸ C.
The potential at point 4.0 m
Given: r = 4.0 m, q = 2.22×10⁻⁸ C, k = 9.0×10⁹ Nm²/C²
Substitute into equation 2
V = 9.0×10⁹(2.22×10⁻⁸)/4
V = 49.95 V
V ≈ 50 V
Hence the potential = 50 V
Logically both masses will collide and well make a reaction. first of all depending on the small mass it will either merge or unite with the big mass or it will bounce away from it . if this happen it will make a reaction that will affect both masses. Hope this helps if it is incorrect please let me know :)
In order to compute the torque required, we may apply Newton's second law for circular motion:
Torque = moment of inertia * angular acceleration
For this, we require the angular acceleration, α. We may calculate this using:
α = Δω/Δt
The time taken to achieve rotational speed may be calculated using:
time = 1 revolution * 2π radians per revolution / 3.5 radians per second
time = 1.80 seconds
α = (3.5 - 0) / 1.8
α = 1.94 rad/s²
The moment of inertia of a thin disc is given by:
I = MR²/2
I = (0.21*0.1525²)/2
I = 0.002
τ = 1.94 * 0.002
τ = 0.004
The torque is 0.004
Answer: vl = 2.75 m/s vt = 1.5 m/s
Explanation:
If we assume that no external forces act during the collision, total momentum must be conserved.
If both cars are identical and also the drivers have the same mass, we can write the following:
m (vi1 + vi2) = m (vf1 + vf2) (1)
The sum of the initial speeds must be equal to the sum of the final ones.
If we are told that kinetic energy must be conserved also, simplifying, we can write:
vi1² + vi2² = vf1² + vf2² (2)
The only condition that satisfies (1) and (2) simultaneously is the one in which both masses exchange speeds, so we can write:
vf1 = vi2 and vf2 = vi1
If we call v1 to the speed of the leading car, and v2 to the trailing one, we can finally put the following:
vf1 = 2.75 m/s vf2 = 1.5 m/s
Answer:
20 hertz of frequency produced.
Explanation:
Here we will find frequency and period should be in second, here given: 0.05 seconds
using the formula:
