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klio [65]
4 years ago
12

Which satellite has the greatest gravitational force with Earth?

Physics
2 answers:
zhannawk [14.2K]4 years ago
7 0

Answer: Option 4, the satellite D.

Explanation: The gravitational force between two objects is given by the formula:

F = G\frac{m1*m2}{r^2}

where m1 and m2 are the masses of the objects, G is a constant, and r is the distance between both objects.

From this equation, you can see that the gravitational force between two objects increments when the masses of the objects increases, and when the distance between the object decreases.

You can see that all the options are at the same distance from the earth, 320km, then the only factor that changes is the mass of the satellite.

And, based on the previous, the satellite with more mass is the satellite that has the greatest gravitational force with the earth, and this would be the satellite D, with amas of 500kg.

EastWind [94]4 years ago
5 0

Answer:

Satellite D has a mass (kg) of 500 and the distance from Earth (km) is 320.

Explanation:

The universal law of gravitation states that the force between two objects in the universe is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

We have to choose the satellite having greatest gravitational force with earth. In all options the distance from the earth is same i.e. 320 km. So, we have to select the satellite having maximum mass because the mass of the earth is constant.

Hence, the correct option is (D) " Satellite D has a mass (kg) of 500 and the distance from Earth (km) is 320 ".

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Water flows with constant speed through a garden hose that goes up to 27.5 cm high. if the water pressure is 132kpa at the botto
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The pressure at the top of the step is 129.303 kilopascals.

Explanation:

From Hydrostatics we find that the pressure difference between extremes of the water column is defined by the following formula, which is a particular case of the Bernoulli's Principle (v_{bottom}\approx v_{top}):

p_{bottom}-p_{top} = \rho\cdot g\cdot \Delta h (1)

p_{bottom}, p_{top} - Total pressures at the bottom and at the top, measured in pascals.

\rho - Density of the water, measured in kilograms per cubic meter.

\Delta h - Height difference of the step, measured in meters.

If we know that p_{bottom} = 132000\,Pa, \rho = 1000\,\frac{kg}{m^{3}}, g = 9.807\,\frac{m}{s^{2}} and \Delta h = 0.275\,m, then the pressure at the top of the step is:

p_{top} = p_{bottom}-\rho\cdot g\cdot \Delta h

p_{top} = 132000\,Pa-\left(1000\,\frac{kg}{m^{3}} \right)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (0.275\,m)

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p_{top} = 129.303\,kPa

The pressure at the top of the step is 129.303 kilopascals.

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