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klio [65]
3 years ago
12

Which satellite has the greatest gravitational force with Earth?

Physics
2 answers:
zhannawk [14.2K]3 years ago
7 0

Answer: Option 4, the satellite D.

Explanation: The gravitational force between two objects is given by the formula:

F = G\frac{m1*m2}{r^2}

where m1 and m2 are the masses of the objects, G is a constant, and r is the distance between both objects.

From this equation, you can see that the gravitational force between two objects increments when the masses of the objects increases, and when the distance between the object decreases.

You can see that all the options are at the same distance from the earth, 320km, then the only factor that changes is the mass of the satellite.

And, based on the previous, the satellite with more mass is the satellite that has the greatest gravitational force with the earth, and this would be the satellite D, with amas of 500kg.

EastWind [94]3 years ago
5 0

Answer:

Satellite D has a mass (kg) of 500 and the distance from Earth (km) is 320.

Explanation:

The universal law of gravitation states that the force between two objects in the universe is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

We have to choose the satellite having greatest gravitational force with earth. In all options the distance from the earth is same i.e. 320 km. So, we have to select the satellite having maximum mass because the mass of the earth is constant.

Hence, the correct option is (D) " Satellite D has a mass (kg) of 500 and the distance from Earth (km) is 320 ".

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Electrical wire with a diameter of .5 cm is wound on a spool with a radius of 30 cm and a height of 24 cm.
kow [346]

Answer:

a)   # lap = 301.59 rad , b)   L = 90.48 m

Explanation:

a) Let's use a direct proportions rule (rule of three). If one turn of the wire covers 0.05 cm, how many turns do you need to cover 24 cm

          # turns = 1 turn (24 cm / 0.5 cm)

         # laps = 48 laps

Let's reduce to radians

        # laps = 48 laps (2 round / 1 round)

       # lap = 301.59 rad

b) Each lap gives a length equal to the length of the circle

          L₀ = 2π R

          L = # turns L₀

          L = # turns 2π R

          L = 48 2π 30

          L = 9047.79 cm

          L = 90.48 m

6 0
3 years ago
two point charges of 3.4 μc and 6.6 μc are 0.20 m apart. what is the electrical potential energy of the system?
Daniel [21]

Explanation:

electrical potential = (6.6-3.4)/0.20

= 16 uc/m

8 0
2 years ago
A light string is wrapped around the edge of the smaller disk, and a 1.50 kg block is suspended from the free end of the string.
LenaWriter [7]

Answer: 7.41 m/s

Explanation: By using the law of of energy, kinetic energy of the brick as it falls equals the potential energy before falling.

Kinetic energy = mv²/2, potential energy = mgh

mv²/2 = mgh

v²/2 = gh

v² = 2gh

v = √2gh

Where g = 9.8 m/s², h = 2.80m

v = √2×9.8×2.8 = 7.41 m/s

7 0
2 years ago
At the surface of Jupiter's moon Io, the acceleration due to gravity is 1.81 m/s2 . A watermelon has a weight of 54.0 N at the s
butalik [34]

Answer:

m=5.51Kg

Explanation:

The weight of an object on Earth is given by W=mg, so we can calculate its mass by doing m=W/g, which for our values is:

m=(54N)/(9.8m/s^2)=5.51Kg

<em>Nothing is being asked</em> about Io but if one wanted to know the weight <em>W'</em> of the watermelon there one just have to do:

W'=ma=(5.51Kg)(1.81m/s^2)=9.97N

4 0
3 years ago
g Two masses are involved in a collision on an axis (one dimensional). One mass is six times the mass of the second. Both masses
statuscvo [17]

Answer:

v₁f = 0.5714 m/s   (→)

v₂f = 2.5714 m/s   (→)

e = 1  

It was a perfectly elastic collision.

Explanation:

m₁ = m

m₂ = 6m₁ = 6m

v₁i = 4 m/s

v₂i = 2 m/s

v₁f = ((m₁ – m₂) / (m₁ + m₂)) v₁i +  ((2m₂) / (m₁ + m₂)) v₂i

v₁f = ((m – 6m) / (m + 6m)) * (4) +  ((2*6m) / (m + 6m)) * (2)  

v₁f = 0.5714 m/s   (→)

v₂f = ((2m₁) / (m₁ + m₂)) v₁i +  ((m₂ – m₁) / (m₁ + m₂)) v₂i

v₂f = ((2m) / (m + 6m)) * (4) + ((6m -m) / (m + 6m)) * (2)

v₂f = 2.5714 m/s   (→)

e = - (v₁f - v₂f) / (v₁i - v₂i)   ⇒   e = - (0.5714 - 2.5714) / (4 - 2) = 1  

It was a perfectly elastic collision.

8 0
2 years ago
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