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kvv77 [185]
3 years ago
12

Think about this hypothetical (not real) situation: Astronaut Dustin and Astronaut Barb are floating in space. The force of grav

ity between Astronaut Dustin and Planet Demi
120,265 Newtons. The force of gravity between Astronaut Barb and Planet Demi is 354,999 Newtons. What can you infer about the relative DISTANCE of each astronaut
from planet Demi? Explain your answer. ​
Physics
1 answer:
Maslowich3 years ago
6 0

The distance between Dustin and the planet is larger than the distance between Barb and the planet

Explanation:

The magnitude of the gravitational force between each astronaut and the planet is given by

F=G\frac{Mm}{r^2}

where :

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2} is the gravitational constant

M is the mass of the planet

m is the mass of the astronaut

r is the separation between the astronaut and the planet

In this problem, we have:

  • The force of gravity between Dustin and the planet is 120,265 N
  • The force of gravity between Barb and the planet is 354,999 N

We see that the force exerted by the Planet on Barb is much greater than the force exerted by the planet on Dustin. Assuming that the mass of Dustin and Barb is similar, then we can say that the magnitude of the force of gravity depends mainly on the distance:

F=\frac{1}{r^2}

And since the force is inversely proportional to the square of the distance, this means that the distance between Dustin and the planet is larger than the distance between Barb and the planet.

Learn more about gravitational force:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

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loris [4]
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3 years ago
If the first stage provides a thrust of 5.31 ​mega-newtons [MN] and the space shuttle has a mass of 5,760,000 ​pound-mass ​[lbm​
zysi [14]

Answer:

The acceleration of the spacecraft is 16,367.62 miles/hr²

Explanation:

Given;

thrust of the spacecraft, F = 5.31 x 10⁶ N

mass of the spacecraft, m = 5,760,000 lbm = 2612692.051 kg

The acceleration of the spacecraft in m/s² is given by Newton's second law of motion;

F = ma

a = F / m

a = \frac{5.31*10^6 \ N}{2612692.051 \ kg}\\\\a = 2.0324 \ m/s^2

The acceleration in miles per hour square is given by;

a =2.0324 \frac{m}{s^2} *\frac{0.0006214 \ mile}{m}*(\frac{3600 \ s}{1 \ hour})^2\\\\  a =2.0324 \frac{m}{s^2} *\frac{0.0006214 \ mile}{m}*\frac{12960000 \ s^2}{1 \ hour^2}\\\\a = 16,367.62 \ miles/hr^2

Therefore, the acceleration of the spacecraft is 16,367.62 miles/hr²

5 0
3 years ago
A pendulum of mass 5.0 kg hangs in equilibrium. A frustrated student walks up to it and kicks the bob with a horizontal force of
Phoenix [80]

Answer:

The length is L = 6.206m and the angle is \theta = 37.752^o.

Explanation:

The period T of the pendulum is related to its length L by

T = 2\pi \sqrt{\dfrac{L}{g} },

where g =9.8m/s^2 is the acceleration due to gravity.

Solving for L we get

L = \dfrac{T^2g}{4\pi^2}

putting in T =5.0s and g =9.8m/s^2 we get:

L = \dfrac{(5.0s)^2*9.8m/s^2}{4\pi^2}

\boxed{L = 6.206m.}

There are two forces acting on the pendulum: The gravitational force mg and the F = 30N student's force. Therefore, the angular displacement \theta that these forces give is

sin(\theta ) = \dfrac{F}{mg}

\theta = sin^{-1}( \dfrac{F}{mg})

putting in F =30N, m =5.0kg, and g =9.8m/s^2 we get

\theta = sin^{-1}( \dfrac{30N}{5.0kg*9.8m/s^2})

\boxed{\theta = 37.752^o.}

4 0
3 years ago
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Explanation:I hope this helps

3 0
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3 years ago
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