Answer:
Rotational inertia of the object is, 
Explanation:
Given that,
Mass of the object, m = 20 kg
Torsion constant of the wire, K = 0.85 N-m
Number of cycles, n = 69
Time, t = 66 s
To find,
The rotational inertia of the object.
Solution,
There exists a relationship between the moment of inertia, time period and the torsion constant of the spring is given by :
Here I is the moment of inertia
T is the time period, and it is equal to the number of cycles per unit time
So, the rotational inertia of the object is 
.
The energy transfer in terms of work has the equation:
W = mΔ(PV)
To be consistent with units, let's convert them first as follows:
P₁ = 80 lbf/in² * (1 ft/12 in)² = 5/9 lbf/ft²
P₂ = 20 lbf/in² * (1 ft/12 in)² = 5/36 lbf/ft²
V₁ = 4 ft³/lbm
V₂ = 11 ft³/lbm
W = m(P₂V₂ - P₁V₁)
W = (14.5 lbm)[(5/36 lbf/ft²)(4 ft³/lbm) - (5/9 lbf/ft²)(11 lbm/ft³)]
W = -80.556 ft·lbf
In 1 Btu, there is 779 ft·lbf. Thus, work in Btu is:
W = -80.556 ft·lbf(1 Btu/779 ft·lbf)
<em>W = -0.1034 BTU</em>
Hello!
Static electricity occurs due to an imbalance in positively and negatively charged atoms. An example of this is when you take your clothes out of the dryer, and feel a slight sting when touching them. Another example of static electricity is lightning.
Current electricity occurs when there is a constant flow of electrons, such as in plug-operated machinery or anything operated using a battery. :)
Answer:
Will it's gonna take around 6s because between the s to hit the top and bottom you divide.
Answer:
164.2°
Explanation:
speed of wind (w) = 45 km/h due south
speed of aircraft (a) = 165 km/h
in what direction (in degrees) should the aircraft head in so as to fly due west?
To get the direction the pilot should fly, we can form a triangle with the data available where
- the direction of the wind (due south) serves as the opposite side
- the direction the pilot would have to fly so he can end up at he west serves as the hypothenuse
- θ is the angle between the direction the pilot would have to fly and the direction the pilot wishes to fly.
- the direction the pilot wishes to fly ( west) will serve as the adjacent side
- all this can be seen from the attached diagram.
now sin θ = 
sin θ = 
θ = 
0.2728
θ = 15.8°
since we are to use the counter-clockwise from east convention our measurement would have to be taken anticlockwise from the east direction, therefore the direction of the aircraft (Ф) = 180-15.8 = 164.2°
