Explanation:
Using kinematics,
s = ut + 0.5at².
We have s = 35.0m, t = 0.50s, a = 2.80m/s².
Substitute in the variables, we have u = 69.3m/s.
This u is only the initial velocity at t1. To find the velocity at t0, we apply a different kinematics equation with different values:
We have t = 5.00s, a = 2.80m/s², v = 69.3m/s.
Using kinematics,
v = u + at.
Substitute in the variables, we have u = 55.3m/s.
Hence the car's initial velocity is 55.3m/s.
Answer:
The force of friction.
Explanation:
Gravity keeps the car on the ground.
Motion Allows the car to move.
The force of speed doesnt make sense.
Friction would cause the car to stop moving.
Answer:
0.0217 m
Explanation:
Ftom the question,
Applying Coulomb's law
F = kqq'/r²............... Equation 1
Where F = Electric Force, q and q' = First and second charge respectively, r = distance between the charges, k = coulomb's constant.
make r the subeject of the equation
r = √[(kqq')/F]............. Equation 2
Given: q = +3.6×10⁻⁸ C, q' = -3.2×10⁻⁸ C, F = -2.2×10⁻² N
Constant: k = 8.98×10⁹ Nm²/C²
Substitute these values into equation
r = √(+3.6×10⁻⁸×-3.2×10⁻⁸×8.98×10⁹/-2.2×10⁻²)
r = √(-103.4489×10⁻⁷/-2.2×10⁻²)
r = √(47.02×10⁻⁵)
r = 21.68×10⁻³
r ≈ 21.7×10⁻³ m.
r ≈ 0.0217 m
Hence the seperation between the two balloons is 0.0217 m
Answer:
Long distance transport of nitrogenous air pollution is important and people who drive are influencing the occurrence of acidic loving lichen species
Explanation: