The gravitational force between two objects is given by:
where
G is the gravitational constant
m1 and m2 are the masses of the two objects
r is their separation
In this problem, the first object has a mass of
, while the second "object" is the Earth, with mass
. The distance of the object from the Earth's center is
; if we substitute these numbers into the equation, we find the force of gravity exerted by the Earth on the mass of 0.60 kg:
Answer:
P=(2 nm, 8mn)
Explanation:
Given :
Position of positively charged particle at origin,
Position of desired magnetic field,
Magnitude of desired magnetic field,
Let q be the positive charge magnitude placed at origin.
<u>We know the distance between the two Cartesian points is given as:</u>
<u>For the electric field effect to be zero at point D we need equal and opposite field at the point.</u>
as we know that the electric field lines emerge radially outward of a positive charge so the second charge will be at equally opposite side of the given point.
assuming that the second charge is placed at (x,y) nano-meters.
Therefore,
and
Yo tengo quince y soy de cali y estoy viviendo en mexico
Answer:
You need to use charts or a calculator to get 56%
Explanation:
Answer:
Er = 231.76 V/m, 27.23° to the left of E1
Explanation:
To find the resultant electric field, you can use the component method. Where you add the respective x-component and y-component of each vector:
E1:
E2:
Keep in mind that the x component of electric field E2 is directed to the left.
∑x:
∑y:
The magnitud of the resulting electric field can be found using pythagorean theorem. For the direction, we will use trigonometry.
or 27.23° to the left of E1.