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nalin [4]
4 years ago
12

How many phases does a solution have?explain

Chemistry
1 answer:
Vikki [24]4 years ago
4 0
Did you perhaps mean the phase of matter? If so, then a solution has only one phase of matter: liquid. It is always almost always liquid because solutions are made up of a solvent and a solute and a solvent is always a liquid. Though, some may come in an emulsion form, but still it can be considered as liquid
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The metal atoms in iron are held together by what
Gwar [14]
They held together by metallic bonds.


Hopefully this has helped! :)
3 0
3 years ago
a 108ml sampl of gas has a mass of 77.96mg at a pressure of 1140mmhg and temperature of 183°c .what is the molar mass of the gas
madam [21]

Answer:

146.85 g/mol

Explanation:

PV=nRT

n=mass/molar mass

covert from mmhg to atm = 0.184 atm

convert from ml to L= 0.108 L

convert from degree C to K= 456.15 K

convert from mg to g= 0.07796g

then rearrange the formula:

n=PV/RT

=(0.184)(0.108)/(0.08206)(456.15)

n= 5.308*10^(-4)

rearrange the n formula interms of molar mass:

Molar mass= mass/n

=0.07796/(5.308*10^-4)

molar mass= 146.85g/mol

3 0
3 years ago
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How do Newton's laws of motion explain why it is important to keep the ice smooth on a hockey rink so that players
andriy [413]

Answer:

How do Newton's laws of motion explain why it is important to keep the ice smooth on a hockey rink so that players can pass a puck as quickly as possible? Smooth ice reduces the unbalanced forces that would slow the hockey puck. A skydiver falls toward the ground at a constant velocity.

Explanation:

3 0
3 years ago
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Calculate the standard potential for the following galvanic cell: Fe(s) | Fe2+(aq) || Ag+(aq) | Ag(s) which has the overall bala
Nataly [62]

Answer:

E° = 1.24 V

Explanation:

Let's consider the following galvanic cell: Fe(s) | Fe²⁺(aq) || Ag⁺(aq) | Ag(s)

According to this notation, Fe is in the anode (where oxidation occurs) and Ag is in the cathode (where reduction occurs). The corresponding half-reactions are:

Anode: Fe(s) ⇒ Fe²⁺(aq) + 2 e⁻

Cathode: Ag⁺(aq) + 1 e⁻ ⇒ Ag(s)

The standard cell potential (E°) is the difference between the standard reduction potential of the cathode and the standard reduction potential of the anode.

E° = E°red, cat - E°red, an

E° = 0.80 V - (-0.44 V) = 1.24 V

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Answer:

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Explanation:

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