The answer is D. Use the equation PV=nRT
P=(.567mol)(.0821)(300K)/4.5L
Answer:
2H₂O (liq) + 2e⁻⇒ H₂ (g) + 2OH⁻ (aq)
Explanation:
In reduction-oxidation reaction two reactions take place, one is oxidation and the other is reduction reaction. In an oxidation reaction, there is the loss of an electron whereas in the reduction reaction there is gain of electron occus.
Reduction reaction occurs on the cathode, in a reduction of water there is gain of 2 electrons to gaseous hydrogen in basic aqueous solution. half-reaction for the reduction of liquid water to gaseous hydrogen in basic aqueous solution-
2H₂O (liq) + 2e⁻⇒ H₂ (g) + 2OH⁻ (aq)
Answer:
Explanation:
2N₂O(g) → 2N₂(g) + O₂(g)
molecular weight of N₂O = 44
∆Hº = –166.7 kJ/mol
44 g of N₂O decomposes to give 166.7 kJ of heat
2.25 g of N₂O decomposes to give 166.7 x 2.25 / 44 kJ of heat
= 8.51 kJ of heat .
I just know it’s not conductive or brittle
