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Ivahew [28]
3 years ago
9

How many formula units are in 9.039 moles of sodium chloride

Chemistry
1 answer:
hodyreva [135]3 years ago
7 0

Answer:

5.443 formula units

Explanation:

use avagadro's number: 1 mole = 6.022 ×10^{23} particles (in this case formula units)

number of mole × 6.022 ×10^{23} = number of particles

9.039 moles × 6.022 ×10^{23} = 5.443 × 10^{24} formula units

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Natasha_Volkova [10]
The total pressure is given by:
P = ∑xiPi
P = 1/2 x 81 + 1/2 x 45
P = 63 kPa
5 0
3 years ago
The SN1 reaction yields Entry field with incorrect answer two (number) products. This is because ______________________. Entry f
vagabundo [1.1K]

Answer:

Four substitution products are obtained. The carbocation that forms can react with either nucleophile (H2O or CH3OH) from either the top or bottom side of the molecule

Explanation:

An SN1 reaction usually involves the formation of a carbocation in the slow rate determining step. This carbocation is now attacked by a nucleophile in a subsequent fast step to give the desired product.

However, the product is obtained as a racemic mixture because the nucleophile may attack from the top or bottom of the carbocation hence both attacks are equally probable.

The attacking nucleophile in this case may be water or CH3OH

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3 years ago
Based on the data table, what evidence best suggests that this might be an object in freefall?
LuckyWell [14K]

Answer:

What datatable? Picture please!

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5 0
3 years ago
Read 2 more answers
What is the molarity of a naoh solution if 39.1 ml of a 0.112 m h2so4 solution is required to neutralize a 25.0-ml sample of the
aleksandrvk [35]
The reaction between NaOH and H₂SO₄ is as follows;
2NaOH + H₂SO₄ ---> Na₂SO₄ + 2H₂O
stoichiometry  of base to acid is 2:1
NaOH is a strong acid and H₂SO₄ is a strong acid, therefore complete ionization into their respective ions takes place.
number of acid moles reacted - 0.112 M / 1000 mL/L x 39.1 mL = 0.0044 mol
the number of base moles required for neutralisation = 0.0044 x 2 = 0.0088 mol
Number of NaOH moles in 25.0 mL - 0.0088 mol
Therefore in 1000 mL  - 0.0088 mol/ 25.0 mL x 1000 mL/L = 0.352 mol/L
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8 0
3 years ago
HIII PLEASE HELP BRUUH
leonid [27]

1. 2Al(s)+6HCl(aq)⇒2AlCl₃(aq)+3H₂(g)

2. 2AgNO₃ (aq) + Cu (s)⇒Cu(NO₃)₂ (aq) + 2Ag (s)

3. 2C₃H₈O(l) + 9O₂(g) ⇒ 6CO₂(g) + 8H₂O(g)

<h3>Further explanation</h3>

There are several reactions that can occur in a chemical reaction: single replacement, double replacement, synthesis, decomposition or combustion, etc.

1.Al(s)+HCl(aq)⇒AlCl₃(aq)+H₂(g)

type : single replacement

balance :

2Al(s)+6HCl(aq)⇒2AlCl₃(aq)+3H₂(g)

2. AgNO₃ (aq) + Cu (s) ⇒ Cu(NO₃)₂ (aq) + Ag (s)

type : single replacement

balance :

2AgNO₃ (aq) + Cu (s)⇒Cu(NO₃)₂ (aq) + 2Ag (s)

3. C₃H₈O + O₂ ⇒ CO₂ + H₂O

type : combustion of alcohol

balance :

2C₃H₈O(l) + 9O₂(g) ⇒ 6CO₂(g) + 8H₂O(g)

4 0
2 years ago
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