All categories

3 years ago

The geometric mean of 4 and 16 is ______. 64 16 12 8

1 answer:

3 0

The geometric mean of $x$ and $y$ is $\sqrt{xy}$ .

So the geometric mean of 4 and 16 is $\sqrt{4\times16}=\sqrt{64}=8$ .

You might be interested in

What is Three-Quarters of Three-Quarters?

madam [21]

3/4 * 3/4

Three quarter meaning 3/4
Of represents *
So the answers is (3*3)/(4*4)=9/16 or 0.5625

8 0

3 years ago

Give one real word example for the following: perimeter, area, volume.

stealth61 [152]

Answer:

perimeter of a children's playground, area of a house, volume of a glass of orange juice.

Step-by-step explanation:

7 0

3 years ago

At a party, everyone shook hands with everybody else. There were 66 handshakes. How many people were at the party?

BARSIC [14]

Total handshakes will be $\\2^{n} = 2^{66}$

4 0

3 years ago

I was wondering if someone would help me with some show your work questions...

adell [148]

Answer:

5/6

Step-by-step explanation:

to add fractions they need to have a common denominator

make 1/3 have a denominator of 18

1/3(6) = 6/18

9/18 + 6/18 = 15/18

15/18 can be simplified to 5/6

4 0

3 years ago

Find the sum of the series Summation from n equals 1 to infinity (StartFraction 3 Over StartRoot n plus 2 EndRoot EndFraction mi

Marizza181 [45]

Looks like the series is supposed to be

$\displaystyle\sum_{n=1}^\infty\frac3{\sqrt{n+2}}-\frac3{\sqrt{n+3}}$

The series telescopes; consider the $k$ th partial sum of the series,

$S_k=\displaystyle\sum_{n=1}^k\frac3{\sqrt{n+2}}-\frac3{\sqrt{n+3}}$

$S_k=\displaystyle\left(\frac3{\sqrt3}-\frac32\right)+\left(\frac32-\frac3{\sqrt5}\right)+\cdots+\left(\frac3{\sqrt{k+1}}-\frac3{\sqrt{k+2}}\right)+\left(\frac3{\sqrt{k+2}}-\frac3{\sqrt{k+3}}\right)$

$\implies S_k=\dfrac3{\sqrt3}-\dfrac3{\sqrt{k+3}}$

As $k\to\infty$ , the second term converges to 0, leaving us with

$\displaystyle\sum_{n=1}^\infty\frac3{\sqrt{n+2}}-\frac3{\sqrt{n+3}}=\frac3{\sqrt3}=\boxed{\sqrt3}}$

7 0

3 years ago