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3 years ago

The geometric mean of 4 and 16 is ______. 64 16 12 8

1 answer:

3 0

The geometric mean of $x$ and $y$ is $\sqrt{xy}$ .

So the geometric mean of 4 and 16 is $\sqrt{4\times16}=\sqrt{64}=8$ .

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SEND HELP!!!!!!!! (image is attached)

Mars2501 [29]

Answer:

y=x+20

Step-by-step explanation:

we have to find the slope

y2-y1/x2-x1

3-2/23-22

1/1

y=1x+b

y-22 = 1(x-2) + b

y=x+20

5 0

3 years ago

Y = x2 - 6x - 8

Usimov [2.4K]

Answer:

I think type answer is A

3 0

3 years ago

Which function has the greater maximum value: f(x) = -2x2 + 8x-1, or g(x),

aleksklad [387]

Answer:

It’s f(x)

Step-by-step explanation:

4 0

2 years ago

Evaluate the expression: −(8 − 12) + 60 + (−4)2. A) 13 B) 20 C) 21 D) −11

k0ka [10]

Answer:

56.

Step-by-step explanation:

= -(8-12)+60+(-4)*2

= -(-4)+60+(-4)*2

= 4+60+(-4)*2

= 4+60+-4*2

= 4+60-4*2

= 4+60-8

= 64-8

= 56

5 0

3 years ago

Write the equation in vertex form and then find the vertex, focus, and directrix of a parabola with equation x=y^2+18y-2

kakasveta [241]

Answer:

Part 1) The vertex is the point (-83,-9)

Part 2) The focus is the point (-82.75,-9)

Part 3) The directrix is $x=-83.25$

Step-by-step explanation:

step 1

Find the vertex

we know that

The equation of a horizontal parabola in the standard form is equal to

$(y - k)^{2}=4p(x - h)$

where

p≠ 0.

(h,k) is the vertex

(h + p, k) is the focus

x=h-p is the directrix

In this problem we have

$x=y^{2} +18y-2$

Convert to standard form

$x+2=y^{2} +18y$

$x+2+81=y^{2} +18y+81$

$x+83=(y+9)^{2}$

This is a horizontal parabola open to the right

(h,k) is the point (-83,-9)

The vertex is the point (-83,-9)

step 2

we have

$x+83=(y+9)^{2}$

Find the value of p

$4p=1$

$p=1/4$

Find the focus

(h + p, k) is the focus

substitute

(-83+1/4,-9)

The focus is the point (-82.75,-9)

step 3

Find the directrix

The directrix of a horizontal parabola is

$x=h-p$

substitute

$x=-83-1/4$

$x=-83.25$

6 0

3 years ago