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valkas [14]
3 years ago
8

Football player A has a mass of 210 pounds and is running at a rate of 5.0 mi/hr. He collides with player B. Player B has a mass

of 190 pounds and is running in the same direction at 3.0 mi/hr. Which of the following statements is true?
-The momentum of player A is equal to that of player B.
-The momentum of player A is greater than that of player B.
-The momentum of player A is less than that of player B.
Physics
2 answers:
Naddika [18.5K]3 years ago
6 0

The equation for momentum is p = mv where p is the omentum, m is the mass and v is the velocity. Calculating the momentum for each football player, player A will have a momentum of 1050 lb-mi/h and player B will have a momentum of 570 lb-mi/h. Therefore, momentum of player A is greater than that of player B.

IgorLugansk [536]3 years ago
3 0

Answer:

the momentum of player A is greater than player B.

Therefore, Option 2 is correct.

Step-by-Step explanation:

We have been given the velocity of the players and mass of the players.

Player A:

Velocity is 5m/hr

Mass 210 pounds

Player B:

Velocity is 3m/hr

Mass 190 pounds

We have a formula for momentum:

p=mv

p is momentum

m is mass

v is velocity

We will  find momentums for both the players:

Momentum of player A:

on substituting the values we get:

p=210\cdot 5=1050 pounds  

Momentum of player B:

on substituting the values we get:

p=190\cdot 3=570 pounds  

Hence, the momentum of player A is greater than player B.

Therefore, Option 2 is correct.




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There are three main measures of central tendency: the mode(the number that occurs most often) the median ( the middle value in the list of numbers) and the mean (the average number in the list of numbers).

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