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Nataly_w [17]
3 years ago
5

At a distance r1 from a point charge, the magnitude of the electric field created by the charge is 226 N/C. At a distance r2 fro

m the charge, the field has a magnitude of 134 N/C. Find the ratio r2/r1.

Physics
2 answers:
jenyasd209 [6]3 years ago
8 0

Explanation:

Below is an attachment containing the solution.

Svetradugi [14.3K]3 years ago
6 0

Answer:

r2/r1 = 1.3

Explanation:

Electric field is given as:

E = kq/r²

At a distance r1,

226 = kq/(r1)² - - - - - - - - - - - - - (1)

At a distance r2,

134 = kq/(r2)² - - - - - - - - - - - - - (2)

From (1),

kq = 226 * (r1)²

From (2),

kq = 134 * (r2)²

Equating and then solving,

134 * (r2)² = 226 * (r1)²

(r2)²/(r1)² = 226/134

(r2)²/(r1)² = 1.687

=> r2/r1 = 1.3

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1)

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2)

The total time taken for the electron in its motion can also be found by using another suvat equation:

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