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Nataly_w [17]
3 years ago
5

At a distance r1 from a point charge, the magnitude of the electric field created by the charge is 226 N/C. At a distance r2 fro

m the charge, the field has a magnitude of 134 N/C. Find the ratio r2/r1.

Physics
2 answers:
jenyasd209 [6]3 years ago
8 0

Explanation:

Below is an attachment containing the solution.

Svetradugi [14.3K]3 years ago
6 0

Answer:

r2/r1 = 1.3

Explanation:

Electric field is given as:

E = kq/r²

At a distance r1,

226 = kq/(r1)² - - - - - - - - - - - - - (1)

At a distance r2,

134 = kq/(r2)² - - - - - - - - - - - - - (2)

From (1),

kq = 226 * (r1)²

From (2),

kq = 134 * (r2)²

Equating and then solving,

134 * (r2)² = 226 * (r1)²

(r2)²/(r1)² = 226/134

(r2)²/(r1)² = 1.687

=> r2/r1 = 1.3

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A 0.4000 kg sample of methanol at 16.0ºC is mixed with 0.4000 kg of water at 85.0ºC. Assuming no heat loss to the surroundings,
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Answer:

T_finalmix = 59.5 [°C].

Explanation:

In order to solve this problem, a thermal balance must be performed, where the heat is transferred from water to methanol, at the end the temperature of the water and methanol must be equal once the thermal balance is achieved.

Q_{water}=Q_{methanol}

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Now replacing:

0.4*4180*(85-T_{final})=0.4*2450*(T_{final}-16)\\142120-1672*T_{final}=980*T_{final}-15680\\157800=2652*T_{final}\\T_{final}=59.5[C]

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A 2 kg book is pushed from rest to a final velocity of 3 m/s. The book travels 2 m. How much force was the book pushed with
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Explanation:

first you have to find accelerarion, it is given that the initial velocity(u) is 3 m/s, distance travelled(s) be 2m finall it came to rest so final velocity be 0m/s

now using the 3rd law of motion

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✌️:)

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3 years ago
Read 2 more answers
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