At a distance r1 from a point charge, the magnitude of the electric field created by the charge is 226 N/C. At a distance r2 fro
m the charge, the field has a magnitude of 134 N/C. Find the ratio r2/r1.
2 answers:
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Buckingham π theorem states that an equation involving a certain number 'n' of variables which are expressible in terms of 'k' independent fundamental physical quantities can be expressed in terms of dimensionless parameters.<span>
p = n - k
Keeping the statement of </span><span>Buckingham Pi Theorem,
We can proceed as follows:
Please see the attachments.I hope it helped
</span>
p = n - k
Keeping the statement of </span><span>Buckingham Pi Theorem,
We can proceed as follows:
Please see the attachments.I hope it helped
</span>
Answer:
1) The amplitude of the motion is approximately 0.274 meters.
2) The total energy of the object at any point of its motion is 16.892 joules.
Explanation:
1) An object under simple harmonic motion is conservative, since there is no dissipative forces acting during motion (i.e. friction, air viscosity). The amplitude of the motion can be found easily by Principle of Energy Conservation by the fact that maximum elastic potential energy (), in joules, is equal to maximum translational kinetic energy (
), in joules:
(1)
Where:
- Spring constant, in newtons per meter.
- Amplitude, in meters.
- Object mass, in kilograms.
- Speed of the object at equilibrium, in meters per second.
If we know that ,
and
, then the amplitude of the motion is:
The amplitude of the motion is approximately 0.274 meters.
2) The total energy of the object (), in joules, is found either by maximum elastic potential energy or by maximum translational kinetic energy, that is: (
,
)
The total energy of the object at any point of its motion is 16.892 joules.
Answer:
Reason for the difference in the ranges of the ball and the cart:
"the average speed of the cart is less than the instant speed of the cart at the time of throwing the ball".
Explanation:
Assuming that the air friction is negligible.
Given that the ball lands on the ground a little before the cart.
So, the range of the ball is more than the range of the cart in the same time interval.
Let the instant speed of the cart is v m/s at the time of throwing the ball in the vertically upward direction, so the speed of the ball in the horizontal direction = v m/s.
Let t be the total time of flight of the ball.
As the gravitational force is acting in the downward direction so it will not change the horizontal velocity of the ball.
So, the range covered by the ball m.
Let u be the average speed of the cart for the time t s (same as the time of flight of ball).
So, the distance by the cart m
As the range of the ball is more than the range of the cart in the same time interval, so
So, the reason for the difference in the ranges of the ball and the cart is "the average speed of the cart is less than the instant speed of the cart at the time of throwing the ball".