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AysviL [449]
3 years ago
12

When an ice cube sits out on a warm day and melts where does the heat go?

Physics
2 answers:
arsen [322]3 years ago
7 0


Here ill explain


There isn't any heat , there is a lack of heat. The sun warms the lack of heat (ice) until its just as warm as everything around it . hoped this helped!

prohojiy [21]3 years ago
7 0

Answer:

When an ice cube sits out on a warm day and melts the heat goes into the ice

Explanation:

When an ice cube sits out on a warm day and melts where does the heat go?

Firstly, temperature is the degree  of hotness or coldness of a body, while heat is the transfer of internal energy due to temperature difference.

When ice melts there is no temperature change. The heat needed to change it from its solid state to its liquid state any noticeable change in temperature is called Heat of fusion Q measured in joules.

Q=mL_{f}

So the heat goes directly to the ice to change its state from solid to liquid without any change in temperature. Only to break its intermolecular force of attraction.

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) Water falls from a height of 60m at the rate of 15kg/s to operate a turbine. The losses due to frictional force are 10% of ene
Angelina_Jolie [31]

Answer:

8100W

Explanation:

Let g = 10m/s2

As water is falling from 60m high, its potential energy from 60m high would convert to power. So the rate of change in potential energy is

P = \dot{E} = \dot{m}gh = 15*10*60 = 9000 J/s or 9000W

Since 10% of this is lost to friction, we take the remaining 90 %

P = 9000*90% = 8100 W

3 0
3 years ago
A tug boat pulls a ship with a constant net horizontal force of 5.00•10*3 N and causes the ship to move through a harbor. How mu
Murljashka [212]

The work done on the ship is 1.5\cdot 10^7 J

Explanation:

The work done by a force on an object is given by:

W=Fd cos \theta

where

F is the magnitude of the force

d is the displacement

\theta is the angle between the direction of the force and of the displacement

In this problem, we have:

F=5.00\cdot 10^3 N (force acting on the ship)

d = 3.00 km = 3000 m (displacement of the ship)

\theta=0^{\circ} (because the force is horizontal, and the displacement is horizontal as well)

Therefore, the work done on the ship is

W=(5.00\cdot 10^3)(3000)(cos 0^{\circ})=1.5\cdot 10^7 J

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

8 0
3 years ago
Winds blowing toward the east are called easterlies.<br><br><br> True or False
eimsori [14]

Answer: False

Explanation:

Winds are named for the cardinal direction they blow from.  Hence, a wind that <em>"blows towards the east"</em>, logically should <u>come from the west </u>and is called a <em>"west wind"</em>.

In thise sense, one of the best examples of this type of wind are the <em>Westerlies</em>, which are are prevailing winds that blow from the west at midlatitudes and have the characteristic that are stronger during winter and weaker during summer.

Therefore, the statement is false.

6 0
3 years ago
Density is given in ____.<br> a. Pa/cm3<br> c. g/s2<br> b. N/m2<br> d. g/cm3
Ainat [17]
Density is defined as  [mass] / [volume] .

The only choice listed with those physical dimensions is 'd' .
3 0
3 years ago
A new ski area has opened that emphasizes the extreme nature of the skiing possible on its slopes. Suppose an ad intones "Free-f
Allushta [10]

Answer:

48.6°

Explanation:

The forward force, F equals the component of the weight along the slope.

So mgsinθ = ma where a = acceleration and θ = angle between the slope and the horizontal.

So a = gsinθ

Since we are given that a = 75%g = 0.75g,

0.75g = gsinθ

sinθ = 0.75

θ = sin⁻¹(0.75)

= 48.6°

5 0
3 years ago
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