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2 years ago

When an ice cube sits out on a warm day and melts where does the heat go?

Physics

2 answers:

arsen [322]2 years ago

7 0

Here ill explain

There isn't any heat , there is a lack of heat. The sun warms the lack of heat (ice) until its just as warm as everything around it . hoped this helped!

prohojiy [21]2 years ago

7 0

Answer:

When an ice cube sits out on a warm day and melts the heat goes into the ice

Explanation:

When an ice cube sits out on a warm day and melts where does the heat go?

Firstly, temperature is the degree of hotness or coldness of a body, while heat is the transfer of internal energy due to temperature difference.

When ice melts there is no temperature change. The heat needed to change it from its solid state to its liquid state any noticeable change in temperature is called Heat of fusion Q measured in joules.

Q=m $L_{f}$

So the heat goes directly to the ice to change its state from solid to liquid without any change in temperature. Only to break its intermolecular force of attraction.

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Many counties in Florida missed many school days in the fall of 2004 due to hurricanes that year. A solution for how to make up

Ivenika [448]

Answer:

108 extended days

Explanation:

Regular school hours a day = 6 hr

No. of school days to make up by extending the regular hours = 3 days

Amount of time added to the regular hours of school = 10 min

No. of extended school days to make up the 3 school days by following the above mentioned criteria be x.

Time of school hours in 3 days = $3\times 6= 18\,hr\,\,\,\, ;or\,\,\, (18\times 60)\,minutes$

$\therefore x=\frac{18\times 60}{10}$

$x=108\,\,days$ are required to make up 3 days of school having 6 hours of regular timing with 10 minutes of add-on time each day.

4 0

3 years ago

When she rides her bike, she gets to her first classroom building 36 minutes faster than when she walks. Of her average walking

postnew [5]

Answer:

$d=2.4\ miles$

Explanation:

Given:

average walking speed, $v_w=3\ mph$

average biking speed, $v_b=12\ mph$

<u>According to given condition:</u>

$t_w=t_b+\frac{36}{60}$

where:

$t_w=$ time taken to reach the building by walking

$t_b=$ time taken to reach the building by biking

We know that,

$\rm time=\frac{distance}{speed}$

so,

$\frac{d}{v_w} =\frac{d}{v_b} +\frac{36}{60}$

$\frac{d}{3}=\frac{d}{12} +\frac{3}{5}$

$d=2.4\ miles$

7 0

3 years ago

Read 2 more answers

Una furgoneta circula por una carretera a 55km/h. Diez km atrás , un coche circula en el mismo sentido a 85km/h ¿ En cuanto tiem

statuscvo [17]

Answer:

t = 0.33h = 1200s

x = 18.33 km

Explanation:

If the origin of coordinates is at the second car, you can write the following equations for both cars:

car 1:

$x=x_o+v_1t$ (1)

xo = 10 km

v1 = 55km/h

car 2:

$x'=v_2t$ (2)

v2 = 85km/h

For a specific value of time t the positions of both cars are equal, that is, x=x'. You equal equations (1) and (2) and solve for t:

$x=x'\\\\x_o+v_1t=v_2t\\\\(v_2-v_1)t=x_o\\\\t=\frac{x_o}{v_2-v_1}$

$t=\frac{10km}{85km/h-55km/h}=0.33h*\frac{3600s}{1h}=1200s$

The position in which both cars coincides is:

$x=(55km/h)(0.33h)=18.33km$

6 0

2 years ago

when a circular plate of metal is heated in an oven, its radius increases at .03 cm/min, at what rate is the area increasing whe

Alinara [238K]

Answer:

Rate of change of area will be $9.796cm^2/min$

Explanation:

We have given rate of change of radius $\frac{dr}{dt}=0.03cm/min$

Radius of the circular plate r = 52 cm

Area is given by $A=\pi r^2$

So $\frac{dA}{dt}=2\pi r\frac{dr}{dt}$

Puting the value of r and $\frac{dr}{dt}$

$\frac{dA}{dt}=2\times 3.14\times 52\times 0.03=9.796cm^2/min$

So rate of change of area will be $9.796cm^2/min$

6 0

2 years ago

PLEASE HELP ME SOMEONE

sasho [114]

I think its B or D, most likely D.

7 0

3 years ago