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2 years ago

13

A person uses a match to light charcoal in a grill. Which statement describes

1 answer:

dolphi86 [110]2 years ago

6 0

Answer:

It is flammable.

Explanation:

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An electromagnet is a type of magnet in which the magnetic field is produced by an electric current. It consists of a solenoid (

aleksklad [387]

Answer:

B using a larger magnetic core

4 0

3 years ago

Read 2 more answers

An engine flywheel initially rotates counterclockwise at 6.55 rotations/s. Then, during 20.9 s, its rotation rate changes to 2.1

11Alexandr11 [23.1K]

Answer:

The average angular acceleration is -2.628 rad/s²

Explanation:

Counterclockwise = positive

Clockwise = -negative

Given;

initial rotation of the flywheel, θ₁ = 6.55 rotation/s

final rotation of the flywheel, θ₂ = - 2.19 rotation/s

The average angular acceleration is given by;

$\alpha = \frac{\delta \theta}{\delta t}\\\\ \alpha =\frac{\theta _2 - \theta_ 1}{t}\\\\ \alpha =\frac{-2.19 -6.55}{20.9} \\\\ \alpha =\frac{-8.74}{20.9}\\\\ \alpha = -0.4182 \ rotation / s^2\\\\ \alpha = \frac{-0.4182 \ rotation}{s^2}*\frac{2\pi \ radian}{rotation}\\\\ \alpha = -2.628 \ rad/s^2$

Therefore, the average angular acceleration is -2.628 rad/s²

7 0

3 years ago

A 0.20 kg mass is oscillating at a small angle from a light string with a period of 0.78 s.

Scorpion4ik [409]

Answer:

L = 15 cm

Explanation:

T = 2π√(L/g)

L = g(T/2π)²

L = 9.8(0.78/2π)²

L = 0.151027... m

L = 15 cm

7 0

3 years ago

Read 2 more answers

1. The Moon's mass is 7.34 x 1022 kg, and it is 3.8 x 105 km away from Earth. Earth's

sineoko [7]

Answer:

2.03 x 10²⁴N

Explanation:

Given parameters:

Mass of moon = 7.34 x 10²²kg

Mass of the earth = 5.97 x 10²⁴kg

Distance = 3.8 x 10⁵km

Unknown:

Gravitational force of attraction = ?

Solution:

To find the gravitational force of attraction between the masses, we use the expression below;

F = $\frac{Gm_{1} m_{2} }{r^{2} }$

G is the universal gravitation constant

m is the mass

1 and 2 represents moon and earth

r is the distance

F = $\frac{6.67 x 10^{-11} x 7.34 x 10^{22} x 5.97 x 10^{24} }{(3.8 x 10^{5})^{2} }$

F = $\frac{2.92 x 10^{35} }{1.44 x 10^{11} }$ = 2.03 x 10²⁴N

8 0

3 years ago

an object at rest starts accelerating if it travels 30 meters to end up going 10 m/s what was it’s acceleration

vfiekz [6]

First we have to calculate the time taken to travel the distance 30 m, is

$t = \frac{distance}{velocity} = \frac{30 \ m}{10 \ m/s } = 3 \ s$ .

Now from equation of motion,

$v = u + at$

Given, $v = 10 \ m/s$ .

As object starts from rest, so u = 0.

Substituting these values in above equation, we get

$10 \ m/s = 0 + a \times 3 \ s \\\\ a = \frac{10}{3} = 3.33 \ m/s^2$ .

Thus, the acceleration is $3.33 \ m/s^2$

3 0

3 years ago