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deff fn [24]
3 years ago
5

The distance traveled is equal to the rate of speed multiplied by the time traveled. if the distance is measured in feet and the

time is measured in minutes, then the rate of speed is expressed in which units? explain how you arrived at your answer.
Mathematics
1 answer:
fgiga [73]3 years ago
8 0
The rate of time is measured in feet per minute. 
<span>Because distance = rate * time, </span>
<span>Then rate = distance / time, which gives you feet / min. </span>
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The price have changed from $120 to $75. By how many
Kitty [74]

Answer:

35.7%

Step-by-step explanation:

The change is 45 dollars. (120-75)

The percent of change is the dollars divided by the original price.

45/120=0.357

Or 35.7%

3 0
3 years ago
Read 2 more answers
A random sample of 20 students yielded a mean of ¯x = 72 and a variance of s2 = 16 for scores on a college placement test in mat
Helen [10]

Answer:

The 98% confidence interval for the variance in the pounds of impurities would be 8.400 \leq \sigma^2 \leq 39.827.

Step-by-step explanation:

1) Data given and notation

s^2 =16 represent the sample variance

s=4 represent the sample standard deviation

\bar x represent the sample mean

n=20 the sample size

Confidence=98% or 0.98

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi square distribution is the distribution of the sum of squared standard normal deviates .

2) Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

On this case the sample variance is given and for the sample deviation is just the square root of the sample variance.

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

df=n-1=20-1=19

Since the Confidence is 0.98 or 98%, the value of \alpha=0.02 and \alpha/2 =0.01, and we can use excel, a calculator or a table to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.01,19)" "=CHISQ.INV(0.99,19)". so for this case the critical values are:

\chi^2_{\alpha/2}=36.191

\chi^2_{1- \alpha/2}=7.633

And replacing into the formula for the interval we got:

\frac{(19)(16)}{36.191} \leq \sigma^2 \leq \frac{(19)(16)}{7.633}

8.400 \leq \sigma^2 \leq 39.827

So the 98% confidence interval for the variance in the pounds of impurities would be 8.400 \leq \sigma^2 \leq 39.827.

7 0
3 years ago
If 5 is decreased by 3 times a number, the result is negative four
JulsSmile [24]
No. It would be negative 5.
7 0
3 years ago
Which ordered pair is included in the solution set to the following system? y &gt; x2 + 3 y &lt; x2 – 3x + 2 (–2, 8) (0, 2) (0,
I am Lyosha [343]

The ordered pair that is a solution of the system is (-2, 8).

<h3>Which ordered pair is included in the solution set to the following system?</h3>

Here we have the system of inequalities:

y > x² + 3

y < x² - 3x + 2

To check which points are solutions of the system, we can just evaluate both inequalities in the given points and see if they are true.

For example, for the first point (-2, 8) if we evaluate it in the two inequalities we get:

8 > (-2)² + 3 = 7

8 <  (-2)² - 3*(-2) + 2 = 12

As we can see, both inequalities are true. So we conclude that (-2, 8) is the solution.

(if you use any other of the 3 points you will see that at least one of the inequalities becomes false).

If you want to learn more about inequalities:

brainly.com/question/18881247

#SPJ1

3 0
2 years ago
2. Flying to Kampala with a tailwind a plane averaged 158 km/h . On the return trip the plane only averaged 112 km/h while flyin
stiv31 [10]

Answer:

Speed of plane in still air = 135 km/h

Speed of wind = 23 km/h

Step-by-step explanation:

Given that:

Speed of plane with the wind = 158km/h

Speed of plane against the wind = 112km/h

Let,

x be the speed of plane

y be the speed of wind

According to given statement;

x+y = 158     Eqn 1

x-y = 112       Eqn 2

Adding Eqn 1 and 2

x+y+x-y=158+112\\2x = 170\\\frac{2x}{2}=\frac{270}{2}\\x=135

Putting x = 135 in Eqn 1

135+y = 158

y = 158-135

y = 23

Hence,

Speed of plane in still air = 135 km/h

Speed of wind = 23 km/h

8 0
3 years ago
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