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Hunter-Best [27]
2 years ago
15

Sketxh the graph of y=(x+3)^3 and state the points where the graph crosses the axes​

Mathematics
1 answer:
gtnhenbr [62]2 years ago
6 0

Answer: the graph crosses the x-axis at x = -3

<u>Step-by-step explanation:</u>

y = (x + 3)³

To find where the graph crosses the x-axis, let y = 0 and solve for x:

0 = (x + 3)³

0 = (x + 3)    with a multiplicity of 3

-3 = x           with a multiplicity of 3.

Since multiplicity is an ODD number, the graph CROSSES the x-axis at x = -3

<em />

<u>Graph:</u>

  • Leading coefficient is POSITIVE so right side goes to +∞
  • Degree of polynomial is ODD so left side goes to -∞

<em>graph is attached</em>

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Hey if you're willing to help me with this, it will be very much appreciated, thanks maties and mates.
Nastasia [14]

Answer:

Width=37in

Length=55in

Step-by-step explanation:

Let x in be the width dimension, the length dimension will be x+18 in. Area of a rectangle is calculated as A=lw. Given  the area as2143 sq in, x can be calculated as:

Area= x(18+x)\\\\=18x+x^2\\\\

#Substitute for every x in our function to find the true value of x:

x=37\\\\A=x^2+18x\\\\=37^2+18\times37\\\\=2035 \ in^2#l=37+18=55in

for x=38:

x=38\\\\A=x^2+18x\\\\=38^2+18\times38\\\\=2128 \ in^2#l=38+18=56in

For x=39:

x=39\\\\A=x^2+18x\\\\=39^2+18\times39\\\\=2223 \ in^2#l=39+1854in

From the calculations above, A television with a width of 37 in and length 55in has its area closest to 2143 sq in.

4 0
2 years ago
I need help ASAP !!!!
labwork [276]
Based on sss because of congruent
8 0
3 years ago
Here is another riddle: The sum of two numbers is less than 2. If we subtract the second number from the first, the difference i
aivan3 [116]

Answer:

Let x, y be the two numbers under consideration. Then, x+y<2 and x-y>1.

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3 years ago
Charlie does a weekly exercise program consisting of cardiovascular work and weight training. Each week, he exercises for at lea
german

Answer:

(x_1,y_1) = (0,9)

(x_2,y_2) = (6,3)

(x_3,y_3) = (6,12)

Step-by-step explanation:

Given

x = hours spent on cardiovascular work

y = hours spent on weight training

From the first statement,

Each week: he spends at least 9 hours

This is represented as:

Total \ge 9

x + y \ge 9

From the second statement,

Each week: he spends a max of 12 hours on weights

This is represented as:

Weight \le 12

y \le 12

From the third statement,

Each week: he spends a max of 6 hours on cardio works

This is represented as:

Cardio \le 6

x \le 6

So, the inequalities are:

x + y \ge 9

y \le 12

x \le 6

See attachment for the graph where the solution are also highlighted

From the attachment, the solutions are:

(x_1,y_1) = (0,9)

(x_2,y_2) = (6,3)

(x_3,y_3) = (6,12)

8 0
3 years ago
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Answer:

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Step-by-step explanation:

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2 years ago
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