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aev [14]
3 years ago
14

To build a road, a company charges a flat fee plus a fee that varies depending on the number of kilometers of road built. The co

st of the work is described by a graph that passes through points (0, 2) and (12, 7), in millions of reais, depending on the number of kilometers built. Therefore, determine the law that represents this function.
Mathematics
2 answers:
Dvinal [7]3 years ago
7 0

Answer:

y = 5/12 x + 2

Step-by-step explanation:

We need to find the equation of a line that passes through two given points.

y = mx + b

First, we find the slope.

m = slope = (y2 - y1)/(x2 - x1)

m = (7 - 2)/(12 - 0) = 5/12

Now we have

y = 5/12 x + b

To find the value of b, we use a point for x and y and solve for b.

y = (5/12)x + b

2 = (5/12)(0) + b

b = 2

The equation is

y = 5/12 x + 2

Goshia [24]3 years ago
4 0

I dont remember that one sorry

Step-by-step explanation:

You might be interested in
A. Does the relationship of weeks passed and total number of followers represent a linear function? (0.5 points) B. What is the
vodomira [7]

The terms "linear function" in mathematics apply to two different but related ideas: A polynomial function of degree zero or one that has a straight line as its graph is referred to as a linear function in calculus and related fields.

a) Yes it does, because the graph of their relationship is a Straight line

b) Independent variables are variables whose variation does not depend on another. Number of works does not depend on followers. Therefore, it is independent

C)number of followers depend on the number of locks passing. It is dependent.

D) Slope = (Y₂- Y₁)/(x₂-x₁) = (100-82)/ (3-0) =  18/3 = 6

It represents the increase in number of followers per week,

E) y-intercept is value of y when x=0

y-intercept = 82. It means his initial number of followers

F) Slope-intercept form → y = mx + c m = slope горе C = y-intercept y = no of followers x= weeks.

Y=6x+82

Learn more about linear function here:

brainly.com/question/4025726

#SPJ10

7 0
2 years ago
Patricia and Joe Payne are divorced. The divorce settlement stipulated that Joe pay $485 a month for their daughter Suzanne unti
zhuklara [117]
\bf \qquad \qquad \textit{Future Value of an ordinary annuity}
\\\\
A=pymnt\left[ \cfrac{\left( 1+\frac{r}{n} \right)^{nt}-1}{\frac{r}{n}} \right]

\bf \begin{cases}
A=
\begin{array}{llll}
\textit{original amount}\\
\textit{already compounded}
\end{array} &
\begin{array}{llll}

\end{array}\\
pymnt=\textit{periodic payments}\to &
\begin{array}{llll}
485\cdot 12\\
\underline{5280}
\end{array}\\
r=rate\to 6\%\to \frac{6}{100}\to &0.06\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{a year, thus once}
\end{array}\to &1\\

t=years\to &4
\end{cases}
\\\\\\


\bf A=5280\left[ \cfrac{\left( 1+\frac{0.06}{1} \right)^{1\cdot  4}-1}{\frac{0.06}{1}} \right]

Joe is making $485 payments monthly, but the amount gets interest on a yearly basis, not monthly, so the amount that yields interest is 485*12

also, keep in mind, we're assuming is compound interest, as opposed to simple interest
3 0
3 years ago
Help me correct this plz
adelina 88 [10]
The answer will be D) 75

To find this it’s easiest to find how many animals there are per percent. So to find this you simply have to divide 30 (the number of cats) by 40 (the percent that makes up) to find the number of animals per percent.

30/40

.75

Then you multiply this by 100 to find how many animals there are total.

.75(100)

75

5 0
3 years ago
Read 2 more answers
I need help figuring this question out
Marysya12 [62]
ANSWER: (4,26)
Comment below if you have any questions or want an explanation:
7 0
3 years ago
Hello, can you please review attached and help me with the answer ?
Elis [28]

Answer:

<em>(a). P(x) = 8x - 112,000 </em>

<em> (b). $80,000 </em>

Step-by-step explanation:

(a). P(x) = R(x) - C(x)

P(x) = 50x - 112,000 - 42x

<em>P(x) = 8x - 112,000</em>

(b). P(24,000) = 8(24,000) - 112,000  = <em>80,000</em>

----------------------------------------

(a). <em>P(x) = 8x - 112,000</em>

7 0
2 years ago
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