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Tatiana [17]
3 years ago
10

Consider a vortex filament of strength in the shape of a closed circular loop of radius R. Obtain an expression for the velocity

induced at the center of the loop in terms of T and R
Engineering
1 answer:
zysi [14]3 years ago
3 0

Answer:

<em>v</em><em> </em>= T/(2R)

Explanation:

Given

R = radius

T = strength

From Biot - Savart Law

d<em>v</em> = (T/4π)* (d<em>l</em> x <em>r</em>)/r³

Velocity induced at center

<em>v </em>= ∫  (T/4π)* (d<em>l</em> x <em>r</em>)/r³

⇒   <em>v </em>= ∫  (T/4π)* (d<em>l</em> x <em>R</em>)/R³  (<em>k</em>)        <em>k</em><em>:</em> unit vector perpendicular to plane of loop

⇒   <em>v </em>= (T/4π)(1/R²) ∫ dl

If l ∈  (0, 2πR)

⇒   <em>v </em>= (T/4π)(1/R²)(2πR)  (<em>k</em>)    ⇒   <em>v </em>= T/(2R)  (<em>k</em>)  

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Answer:

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L =  0.00841549 / 1.4

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L = 6 × 10⁻³ × 1000 mH

L = 6 mH

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b)

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Refer below for the explanation.

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