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3 years ago

What’s the answer???

Engineering

1 answer:

Zanzabum3 years ago

3 0

D IS THE ANSWER ❤︎❤︎❤︎spread love and share knowledge

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Which ranks careers in the Architecture and Construction career cluster based on the typical number of years for each degree, go

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5. Usually, loads of more than

Reika [66]

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3 years ago

For a steel alloy it has been determined that a carburizing heat treatment of 7 hour duration will raise the carbon concentratio

Aliun [14]

Answer:

18.6h

Explanation:

To solve this Duck's second law in form of Diffusion will be used.

Also note that since the temperature is constant D (change) will also be constant.

Please go through the attached files for further explanation and how the answer Is gotten.

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3 years ago

James wants to qualify for IDP, ARE, and licensure. Which degree would be required in order to qualify for two-year Master of Ar

Elodia [21]

Answer:

The correct option is;

C. A four-year pre-professional architecture degree

Explanation:

A student that already has a Pre-Professional four year degree such as a Bachelor of Arts (B.A.) or Bachelors of Science (B.S.) in architecture and has therefore, completed a certain amount of basic coursework related to architecture, whilst studying for their undergraduate degree can receive professional training/education by applying to a 2 year M.Arch. program whereby the combined bachelors and M.Arch program combined is known as a four-plus-two program

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3 years ago

By efficiency, we generally mean the ratio of the desired output to the required input. That is, efficiency is a measure of what

natulia [17]

Answer:

The answers to the question is as follows

a. 0.3425 or 34.25% efficiency

b. 0.8432 ≅ 0.84

c. 138,871 Kilowatts ≈ 140 kW

Explanation:

a.) Overall efficiency =η,overall = $\frac{Heat equivalent of electric power}{Heat of coal cumbustion}$ i.e (heat amounting to the quantity of produced electric power) / (Heat produced by coal combustion)

The heat equivalent of electric power → 95,000 kw ≡ 324,153,410 BTUs per Hour

heat produced by coal combustion = 72,800 ibm/hr which produces 13000 Btu/ibm-coal hence the amount of heat produced by the coal =

72,800 ibm/hr × 13,000 Btu/ibm-coal = 946400000 Btu/hr

Therefore overall plant efficiency = 324153410/946400000 = 0.3425

which is 34.25% efficiency

b.) Energy added to the steam from combustion of coal = 1140 Btu/lbm-steam

Steam power plant generates = 700,000 lbm/hr

Energy added to the steam per hour from the coal = 700000×1140 = 798000000 Btu/hr,

Fraction of the energy released from the coal that is added to the steam =798000000/946400000 = 0.8432 of the energy released from the coal is added to the steam

c.) The amount of heat rejection is given by

Energy in steam - heat equivalent of energy of power output

798000000 Btu/hr -324,153,410 Btu/Hr = 473846590 Btu/Hr or 138,871 Kilowatts

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3 years ago