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denis23 [38]
3 years ago
10

What is acceleration?

Physics
1 answer:
bonufazy [111]3 years ago
4 0
I'm pretty sure it's A.
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horizontal clothesline is tied between 2 poles, 14 meters apart. When a mass of 3 kilograms is tied to the middle of the clothes
lbvjy [14]

Answer:

The tension is  T =  103.96N

Explanation:

The free body diagram of the question is shown on the first uploaded image From the question we are told that

           The distance between the two poles is D =14 m

          The mass tied between the two cloth line is  m = 3Kg

         The distance it sags is d_s = 1m

The objective of this solution is to obtain the magnitude of the tension on the ends of the  clothesline

Now the sum of the forces on the y-axis is zero assuming  that the whole system is at equilibrium

       And this can be mathematically represented as

                             \sum F_y = 0

 To obtain \theta we apply SOHCAHTOH Rule

 So    Tan \theta = \frac{opp}{adj}

          \theta = tan^{-1} [\frac{opp}{adj} ]

            = tan^{-1} [\frac{1}{7}]

          =8.130^o

=>  \  \ \ \ \ \ \ \ 2T sin\theta -mg =0

=>  \  \ \ \ \ \ \ \ T =\frac{mg}{2 sin\theta}

=>  \  \ \ \ \ \ \ \ T = \frac{3 * 9.8 }{2 sin \theta }

=>  \  \ \ \ \ \ \ \  T =\frac{29.4}{2sin(8.130)}

=>  \  \ \ \ \ \ \ \  T = 103.96N

             

                 

5 0
3 years ago
Read 2 more answers
3) All numbers that are divisible by both 3 and 5 are also divisible by 10. Which of the following numbers can be used to show t
zlopas [31]

Answer:

answer E

Explanation:

cuz its 45 is divisible by 3 and 5 but not 10

8 0
2 years ago
When climbing a steep hill, would you want a larger or smaller bicycle gear?
DochEvi [55]

Answer:

Usually when climbing, it's best to be in the small front ring and the largest back ring. If your cadence is about 100 rpm, then whatever gear you're in is fine. It depends on the road, but as long as your pedaling is at a level you're comfortable with, you're fine.

Explanation:

Google answer by the way.

3 0
3 years ago
A transformer connected to a 120-v(rms) at line is to supply 13,000V(rms) for a neon sign.
lyudmila [28]

Answer:

(a) 108

(b) 110.500 kW

(c) 920.84 A

Solution:

As per the question:

Voltage at primary, V_{p} = 120\ V          (rms voltage)

Voltage at secondary, V_{s} = 13000\ V  (rms voltage)

Current in the secondary, I_{s} = 8.50\ mA  

Now,

(a) The ratio of secondary to primary turns is given by the relation:

\frac{N_{s}}{N_{p}} = \frac{V_{s}}{V_{s}}

where

N_{p} = No. of turns in primary

N_{s} = No. of turns in secondary

\frac{N_{s}}{N_{p}} = \frac{13000}{120} ≈ 108

(b) The power supplied to the line is given by:

Power, P = V_{s}I_{s} = 13000\times 8.50 = 110.500\ kW

(c) The current rating that the fuse should have is given by:

\frac{V_{s}}{V_{p}} = \frac{I_{p}}{I_{s}}

\frac{13000}{120} = \frac{I_{p}}{8.50}

I_{p} = \frac{13000}{120}\times 8.50 = 920.84\ A

 

6 0
3 years ago
DEFINA O QUE É AGILIDADE?
faltersainse [42]

Answer:

  • sorry

Explanation:

sorry lol i don't know

3 0
3 years ago
Read 2 more answers
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