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natka813 [3]
3 years ago
8

A 20 kilogram ball rolls down a 10 meter ramp at the rate of 15 meters per second. The kinetic energy is joules

Physics
1 answer:
kobusy [5.1K]3 years ago
3 0

Answer:2250J

Explanation:

mass(m)=20kg

velocity(v)=15m/s

Kinetic energy=(m x v^2)/2

Kinetic energy =(20 x 15^2)/2

Kinetic energy =(20x15x15)/2

Kinetic energy=4500/2

Kinetic energy=2250J

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How dose the speed of the sound differ in water, iron, and Helium?
stepladder [879]

Answer:

             air       water      iron        helium

v(m/s)   280     2200      17780     39682

Explanation:

The speed of a wave depends on the physical properties of the medium where it travels, in the case of a longitudinal wave such as sound, it depends on the resistance to deformation (volume modulus and the density of the medium

         v = \sqrt{ \frac{B}{ \rho } }

in the mentioned materials they are constant  

             air       water      iron        helium

B           1 10⁵    2.2 10⁹    140 10⁹   0.05 10⁹

ρ           1.28     997        7874       1.26

v(m/s)   280     2200      17780     39682

4 0
2 years ago
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Serggg [28]

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6 0
3 years ago
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If a length and diameter of a pencil are both multiplied by 10, then the volume is multiplied by ?
Feliz [49]

Answer:

1000

Explanation:

If we model the pencil as a cylinder:

V = π r² h

Or, in terms of diameter:

V = π/4 d² h

If we multiply d and h by 10:

V = π/4 (10 d)² (10 h)

V = 1000 (π/4 d² h)

The volume increases by a factor of 1000.

5 0
3 years ago
Car A is traveling west at 40 mi/h and car B is traveling north at 40 mi/h. Both are headed for the intersection of the two road
Gwar [14]

Explanation:

It is given that,

    \frac{dx}{dt} = -40 mi/h,     \frac{dx}{dt} = -40 mi/h

The negative sign indicates that x and y are decreasing.

We have to find \frac{dz}{dt}. Equation for the given variables according to the Pythagoras theorem is as follows.

              z^{2} = x^{2} + y^{2}

Now, we will differentiate each side w.r.t 't' as follows.

        2z\frac{dz}{dt} = 2x\frac{dx}{dt} + 2y\frac{dy}{dt}

or,          \frac{dz}{dt} = \frac{1}{z}(x\frac{dx}{dt} + y\frac{dy}{dt})

So, when x = 4 mi, and y = 3 mi then z = 5 mi.

As,       \frac{dz}{dt} = \frac{1}{z}(x\frac{dx}{dt} + y\frac{dy}{dt})

                       = \frac{1}{5}(4 \times (-40) + 3 \times (-40))

                       = \frac{-140 - 120}{5}

                       = 52

Thus, we can conclude that the cars are approaching at a rate of 52 mi/h.

7 0
3 years ago
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