Turn lights off, unplug electronics, and use solar energy
Answer:
g = 11.2 m/s²
Explanation:
First, we will calculate the time period of the pendulum:
![T = \frac{t}{n}](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7Bt%7D%7Bn%7D)
where,
T = Time period = ?
t = time taken = 135 s
n = no. of swings in given time = 98
Therefore,
![T = \frac{135\ s}{98}](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7B135%5C%20s%7D%7B98%7D)
T = 1.38 s
Now, we utilize the second formula for the time period of the simple pendulum, given as follows:
![T = 2\pi \sqrt{\frac{l}{g}}](https://tex.z-dn.net/?f=T%20%3D%202%5Cpi%20%5Csqrt%7B%5Cfrac%7Bl%7D%7Bg%7D%7D)
where,
l = length of pendulum = 54 cm = 0.54 m
g = acceleration due to gravity on the planet = ?
Therefore,
![(1.38\ s)^2 = 4\pi^2(\frac{0.54\ m}{g} )\\\\g = \frac{4\pi^2(0.54\ m)}{(1.38\ s)^2}](https://tex.z-dn.net/?f=%281.38%5C%20s%29%5E2%20%3D%204%5Cpi%5E2%28%5Cfrac%7B0.54%5C%20m%7D%7Bg%7D%20%29%5C%5C%5C%5Cg%20%3D%20%5Cfrac%7B4%5Cpi%5E2%280.54%5C%20m%29%7D%7B%281.38%5C%20s%29%5E2%7D)
<u>g = 11.2 m/s²</u>
Answer:
450 kJ
Explanation:
Q = mCΔT
where Q is heat (energy),
m is mass,
C is specific heat capacity,
and ΔT is the temperature change.
Q = (1.2 kg) (4180 J/kg/°C) (100°C − 10°C)
Q = 451,440 J
Q ≈ 450 kJ
Answer:
The answer is B, velocity.
Explanation:
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Answer:
C-D
Explanation:
As you can see from the graph, the distance from A to B was from 0 m to 6 m in a duration of 3 seconds.
Divide 6 meters by 3 seconds to find the speed:
6 ÷ 3 = 2 m/s
B-C is not moving due to a straight line as said in the graph, so speed is
0 m/s.
There is also C-D since the car traveled from a distance of 9 meters
(6 -(-3) = 9) in 3 seconds too. (NOTE: The graph line going down does not mean it is slowing down, but rather going to a certain distance like going backwards)
Divide 9 meters by 3 seconds to get the speed:
9 ÷ 3 = 3 m/s
Between A-B, B-C, and C-D, C-D has the fastest speed recorded with 3 m/s.
A-D does not count here as the line has no connection between point A and point D.
Cheers!