Answer:
3893.99675 N
Explanation:
= 125 N
= 
= 
From Pascal's law

The force that the liquid exerts on the bottom of the bottle is 3893.99675 N
Answer:
The forces experienced by the middle particle are attractive, and the net force will remain the same (0) if and only if the distances of the sides particles to the middle particle are the same.
Explanation:
In example 20.3 the forces experienced by the middle particle are repulsive because all the particles are positive, for the case in which the particles on the sides are replaced for negative charge particles the forces experienced by the middle particle are attractive. Regarding the net force, because we don't know the distances we can not give a definitive answer, what we can say is that if the distances from the middle particle to the sides particles are the same the net force is zero for both cases (remain unchanged).
Answer:
∴The air cannot be made to flow in with the given pump at the given conditions.
Explanation:
Given:
- gauge pressure of bicycle tyre,

- length of cylinder of the pump,

- area of the the cylinder of the pump,

- we have the density of air at STP,

The piston must be pushed more than the pressure inside the tyre:


∴The air cannot be made to flow in with the given pump at the given conditions.
The answer is:
Hopping.
Explanation:
Hopping is done by taking off on one foot and landing back on that same foot. Hopping is done in shorter intervals, meaning you usually don't travel large distances through a single hop. Hopping is categorized as short leaps for its small distance covered singularly, and each hop is done only on one foot.
<em>(Think about if one of your feet/legs is injured or asleep. If you wanted to go from say the living room to the kitchen, but didn't wish to move that leg or foot, you would likely hop on one foot to get to the destination.)</em>
Answer:
60 V
Explanation:
Let the potential on capacitor be V . This will be equal to voltage of the source .
During discharge this voltage of capacitor will create current .
V / 120 = .5
V = 60 V
So this would have been the voltage of the source . So voltage of source
= 60 V