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zlopas [31]
3 years ago
9

Calculate the ph of the solution 0.2M Mg(OH)2

Chemistry
2 answers:
Kipish [7]3 years ago
6 0

Mg(OH)2 is base

Oh = 0.2 x 2 = .4

Poh = - Log (.4)

= .3979

Ph + Poh = 14

Ph = 14 - .3979

= 13.60

Dennis_Churaev [7]3 years ago
3 0

13.60 is the answer

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