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alina1380 [7]
4 years ago
5

A molecule of water (H2O) is made from combining two hydrogen atoms and one oxygen atomc. thermallya. physicallyd. chemicallyb.

ionically

Physics
1 answer:
labwork [276]4 years ago
3 0
It is chemically combined
You might be interested in
An infinitely long wire carrying a 25-A current in a the positive x-direction is places along the xaxis in the vicinity of a 20-
Masteriza [31]

Answer:

0.2 A, clockwise direction

Explanation:

We are given that

Current,I=25 A

Number of turns=n=20

Magnetic field at center of r the loop=B=0

d=2 m

We have to find the direction and magnitude of current flowing in the loop.

Magnetic field due to current I

B=\frac{\mu_0 I}{2\pi d}\hat{z}

Magnetic field due to I'

B'=-\frac{\mu_0 nI''}{2a}\hat{z}

a=1 m

Net magnetic is zero

Therefore, B+B'=0

\frac{\mu_0 I}{2\pi d}\hat{z}-\frac{\mu_0 nI''}{2a}\hat{z}=0

\frac{\mu_0 I}{2\pi d}\hat{z}=\frac{\mu_0 nI''}{2a}\hat{z}

\frac{I}{\pi d}=\frac{I'n}{a}

I'=\frac{aI}{\pi d n}=\frac{25\times 1}{3.14\times 2\times 20}=0.2 A

Where \pi=3.14

Direction: Clockwise

8 0
3 years ago
Determine the centroid of the shaded area shown in figure 2. Determine the moment of inertia about y-axis of the shaded area sho
Nady [450]

Answer:

  • centroid: (x, y) = (81.25 mm, 137.5 mm)
  • I = 8719.31 mm^2    for unit mass

Explanation:

Finding the desired measures requires we know a differential of area. That, in turn, requires we have a way to describe a differential of area. Here, we choose to use a vertical slice, which requires we know the area boundaries as a function of x.

The upper boundary is a line with a slope of 125/156.25 = 0.8, and a y-intercept of 125. That is, ...

  y1 = 0.8x +125

The lower boundary is given in terms of y, but we can solve for y to find ...

  100x = y^2

  y2 = 10√x

Then our differential of area is ...

  dA = (y1 -y2)dx

__

The centroid is found by computing the first moment about the x- and y-axes, and dividing those values by the area of the figure.

The area will be ...

  \displaystyle A=\int_0^{156.25}{dA}=\int_0^{156.25}{(y_1-y_2)}\,dx

The y-coordinate of the centroid is ...

  \displaystyle \overline{y}=\dfrac{S_x}{A}=\dfrac{1}{A}\int_0^{156.25}{\dfrac{y_1+y_2}{2}}\,dA=\dfrac{1}{A}\int_0^{156.25}{\dfrac{y_1+y_2}{2}(y_1-y_2)}\,dx=137.5

Similarly, the x-coordinate is ...

  \displaystyle \overline{x}=\dfrac{S_y}{A}=\dfrac{1}{A}\int_0^{156.25}{x}\,dA=\dfrac{1}{A}\int_0^{156.25}{x(y_1-y_2)}\,dx=81.25

That is, centroid coordinates are (x, y) = (81.25, 137.5) mm.

__

The moment of inertia is the second moment of the area. If we normalize by the "mass" (area), then the integral looks a lot like the one for \overline{x}, but multiplies dA by x^2 instead of x.

The attachment shows that value to be ...

  I ≈ 8719.31 mm^2 (normalized by area)

The area is 16276.0416667 mm^2, if you want to "un-normalize" the moment of inertia.

7 0
3 years ago
Determine the required height h of the roller coaster so that when it is essentially at rest at the crest of the hill A it will
Dmitriy789 [7]

Answer:

a) 39.37 m

b) 26.25 m

Explanation:

Given

speed of the roller coaster, v = 100 km/h = 100 * (1000/3600) m/s = 27.78 m/s

Using the law of conservation of energy.

Potential Energy = Kinetic Energy

mgh = 1/2mv²

gh = 1/2v²

h = v²/2g

h = 27.78² / 2 * 9.8

h = 771.7284 / 19.6

h = 39.37 m

Also,

kmg - mg = mv²/p

kg - g = v²/p

p = v²/g(k - 1)

p = 27.78² / 9.8(4 - 1)

p = 771.7284 / 29.4

p = 26.25 m

Therefore, the height of the roller coaster is 39.37 m and the radius of curvature required is 26.25 m

8 0
3 years ago
The universe is made up of __________.
vekshin1
Thousands of galaxies
7 0
3 years ago
Read 2 more answers
A rollercoaster moves from the bottom of a hill and approaches the top of the hill. If friction between the wheels and the track
Fudgin [204]

Answer:

The kinetic energy decreases, and gravitational potential energy increases.

Explanation:

The rollercoaster will slow down as it goes up the hill, so kinetic energy should not increase.

4 0
3 years ago
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