Ask question

Ask question

All categories

2 years ago

7

Anaerobic transmission is when you touch a contaminated surface true or false

1 answer:

Keith_Richards [23]2 years ago

5 0

True because my mom said to me this morning that i have to take my breakfast

You might be interested in

A solid uniformly charged insulating sphere has uniform volume charge density p and radius R. Apply Gauss's law to determine an

RUDIKE [14]

Answer:

electric field E = (1 /3 e₀) ρ r

Explanation:

For the application of the law of Gauss we must build a surface with a simple symmetry, in this case we build a spherical surface within the charged sphere and analyze the amount of charge by this surface.

The charge within our surface is

ρ = Q / V

Q ’= ρ V '

The volume of the sphere is V = 4/3 π r³

Q ’= ρ 4/3 π r³

The symmetry of the sphere gives us which field is perpendicular to the surface, so the integral is reduced to the value of the electric field by the area

I E da = Q ’/ ε₀

E A = E 4 πi r² = Q ’/ ε₀

E = (1/4 π ε₀) Q ’/ r²

Now you relate the fraction of load Q ’with the total load, for this we use that the density is constant

R = Q ’/ V’ = Q / V

How you want the solution depending on the density (ρ) and the inner radius (r)

Q ’= R V’

Q ’= ρ 4/3 π r³

E = (1 /4π ε₀) (1 /r²) ρ 4/3 π r³

E = (1 /3 e₀) ρ r

4 0

3 years ago

A 15 n net force is used to move a 5kg box. What is the resulting acceleration?

Mamont248 [21]

Answer:3 m/s

Explanation:

8 0

3 years ago

The Mars Curiosity rover was required to land on the surface of Mars with a velocity of 1 m/s. Given the mass of the landing veh

Aliun [14]

Answer:

The value is $A = 39315 \ m^2$

Explanation:

From the question we are told that

The velocity which the rover is suppose to land with is $v = 1 \ m/s$

The mass of the rover and the parachute is $m = 2270 \ kg$

The drag coefficient is $C__{D}} = 0.5$

The atmospheric density of Earth is $\rho = 1.2 \ kg/m^3$

The acceleration due to gravity in Mars is $g_m = 3.689 \ m/s^2$

Generally the Mars atmosphere density is mathematically represented as

$\rho_m = 0.71 * \rho$

=> $\rho_m = 0.71 * 1.2$

=> $\rho_m = 0.852 \ kg/m^3$

Generally the drag force on the rover and the parachute is mathematically represented as

$F__{D}} = m * g_{m}$

=> $F__{D}} = 2270 * 3.689$

=> $F__{D}} = 8374 \ N$

Gnerally this drag force is mathematically represented as

$F__{D}} = C__{D}} * A * \frac{\rho_m * v^2 }{2}$

Here A is the frontal area

So

$A = \frac{2 * F__D }{ C__D} * \rho_m * v^2 }$

=> $A = \frac{2 * 8374 }{ 0.5 * 0.852 * 1 ^2 }$

=> $A = 39315 \ m^2$

8 0

3 years ago

A 46 g domino slides down a 30 degrees incline at a constant speed. What is the coefficient of friction?

blondinia [14]

Answer:

40

Explanation:

30

6 0

3 years ago

T-Joe (65 kg) is running at 3 m/s. T-Brud (50 kg) is running at 4 m/s. What would be T-Joe's momentum?

Debora [2.8K]

Answer:

$P_J=195N$

Explanation:

From the question we are told that

$Mass\ of T-joe\ M_J=65\\Velocity\ of T-joe\ V_J=3m/s\\Mass of\ T-Brud\ M_B=50kg\\Velocity\ of T-Brud\ V_B=3m/s\\$

Generally the equation for momentum is mathematically given by

$P=mv$

Therefore

T-Joe momentum $P_J$

$P_J=65*3$

$P_J=195N$

5 0

2 years ago