3 years ago

The universe is made up of __________.

Physics

2 answers:

vitfil [10]3 years ago

8 0

Answer:

i am a little late but.... who cares anyway the answer is

thousands of galaxies

Explanation:

i took the test

vekshin13 years ago

7 0

Thousands of galaxies

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| The electric field 5.0 cm from a very long charged wire is (2000 N/C, toward the wire). What is the charge (in nC) on a 1.0-cm

Serggg [28]

Answer:

The charge is 0.056 nC.

Explanation:

Given that,

Electric field = 2000 N/C

Distance = 5.0 cm

We need to calculate the charge density

Using formula of charge density

$E=\dfrac{\lambda}{2\pi\times\epsilon_{0}r}$

$\lambda=2\pi\times\epsilon_{0}\times r\times E$

Put the value into the formula

$\lambda=2\pi\times8.85\times10^{-12}\times5.0\times10^{-2}\times2000$

$\lambda=5.56\times10^{-9}\ C/m$

We need to calculate the charge in 1.0 cm

Using formula of charge

$Charge = \lambda\times\text{length of segment}$

$Charge =5.56\times10^{-9}\times1.0\times10^{-2}$

$Charge=0.056\times10^{-9}\ C$

$Charge=0.056\ nC$

Hence, The charge is 0.056 nC.

3 0

3 years ago

I need help with this one <br><br> Coulombs law <br><br> 100 points and brainliest

Ganezh [65]

Answer:

my dad is a physics professor so when he comes home i will tell him to answer the question for you

3 0

3 years ago

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HELP THIS IS LATE How does the size and temperature of the Sun compare to other stars in the Milky Way galaxy?

Verizon [17]

Answer:ya.\

Explanation:

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3 years ago

4. As a 500 N woman sits on the floor, the floor exerts a force on her of

monitta

Answer: 1000

Explanation:

Its double her weight

7 0

3 years ago

A magnetic field has a magnitude of 0.078 T and is uniform over a circular surface whose radius is 0.10 m. The field is oriented

oee [108]

Answer:

Magnetic flux, $\phi=2.22\times 10^{-3}\ Wb$

Explanation:

It is given that,

Magnitude of the magnetic field, B = 0.078 T

Radius of circular loop, r = 0.1 m

The field is oriented at an angle of θ = 25° with respect to the normal to the surface. The magnetic flux through the surface is given by :

$\phi=BA\ cos\theta$

$\phi=0.078\times \pi \times (0.1)^2\ cos(25)$

$\phi=0.00222\ Wb$

$\phi=2.22\times 10^{-3}\ Wb$

So, the magnitude of magnetic flux through the surface is $2.22\times 10^{-3}\ Wb$ . Hence, this is the required solution.

4 0

4 years ago