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svetlana [45]
4 years ago
15

Which one is equivalent to 28% by mass? 0/1 point O 28 g solute perg of solvent 28 g solute per g of solution 28 g solute per 10

0 g of solvent 28 g solute per 100 g of solution Incorrect
Chemistry
1 answer:
astra-53 [7]4 years ago
3 0

Answer:

28 g solute per 100 g of solution

Explanation:

28% mass means that in all your solution you have 28% of your solute, you could use grames/grames, ml/ml or whatever you want to. So if you are working with a 100 grams solution, 28 grams of that solution must be solute if you want a 28% mass. So, the correct answer is 28 g solute per 100 g of solution.

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What is the freezing point of a solution prepared from 45.0 g ethylene glycol (C2H6O2) and 85.0 g H2O? Kf of water is 1.86°C/m.
Andrews [41]

Answer:

T_{sol}=-15.9\°C

Explanation:

Hello,

In this case, we can analyze the colligative property of solutions - freezing point depression - for the formed solution when ethylene glycol mixes with water. Thus, since water freezes at 0 °C, we can compute the freezing point of the solution as shown below:

T_{sol}=T_{water}-i*m*Kf

Whereas the van't Hoff factor for this solute is 1 as it is nonionizing and the molality is:

m=\frac{mol_{solute}}{kg\ of\ water}=\frac{45.0g*\frac{1mol}{62g} }{85.0g*\frac{1kg}{1000g} } =8.54m

Thus, we obtain:

T_{sol}=0\°C+(-8.54m*1.86\frac{\°C}{m} )\\\\T_{sol}=-15.9\°C

Best regards.

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The water does not change it's H2O chemical makeup because salt was dissolved into it.
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