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viktelen [127]
3 years ago
9

What is the freezing point of a solution prepared from 45.0 g ethylene glycol (C2H6O2) and 85.0 g H2O? Kf of water is 1.86°C/m.

Chemistry
1 answer:
Andrews [41]3 years ago
6 0

Answer:

T_{sol}=-15.9\°C

Explanation:

Hello,

In this case, we can analyze the colligative property of solutions - freezing point depression - for the formed solution when ethylene glycol mixes with water. Thus, since water freezes at 0 °C, we can compute the freezing point of the solution as shown below:

T_{sol}=T_{water}-i*m*Kf

Whereas the van't Hoff factor for this solute is 1 as it is nonionizing and the molality is:

m=\frac{mol_{solute}}{kg\ of\ water}=\frac{45.0g*\frac{1mol}{62g} }{85.0g*\frac{1kg}{1000g} } =8.54m

Thus, we obtain:

T_{sol}=0\°C+(-8.54m*1.86\frac{\°C}{m} )\\\\T_{sol}=-15.9\°C

Best regards.

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Vascular tissue

From Wikipedia, the free encyclopedia

Jump to navigationJump to search

Cross section of celery stalk, showing vascular bundles, which include both phloem and xylem.

Detail of the vasculature of a bramble leaf.

Translocation in vascular plants

This article is about vascular tissue in plants. For transportation in animals, see Circulatory system.

Vascular tissue is a complex conducting tissue, formed of more than one cell type, found in vascular plants. The primary components of vascular tissue are the xylem and phloem. These two tissues transport fluid and nutrients internally. There are also two meristems associated with vascular tissue: the vascular cambium and the cork cambium. All the vascular tissues within a particular plant together constitute the vascular tissue system of that plant.

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6 0
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Hope this helps!
</span>
4 0
4 years ago
Read 2 more answers
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