Answer:
C18H38(s) + O2(g) → CO₂(g) + H₂O(g).
Explanation:
C₁₈H₃₈ is called Octadecane and it is an Alkane as the molecular formula follows the general formula of Alkanes which is CnH2n+2 .
C₁₈H₃₈ reacts with Oxygen and forms Carbon Dioxide (CO₂) and Water (H₂O).
We can say that on oxidation Octadecane gives Carbon Dioxide (CO₂) and Water (H₂O) because on passing Oxygen over Octadecane the above products are formed.
C18H38(s) + O2(g) → CO₂(g) + H₂O(g).
Answer:
Option C 28 Proton 31 neutron 26 elecrtons
Explanation:
Answer:
Ea = 210.5kJ/mole
Explanation:
When the reaction:
O3 + NO → O2 + NO2
Occurs, requires 10.7kJ/mole and releases -199.8kJ/mole.
For the forward reaction:
O2 + NO2 → O3 + NO
The Ea is the sum of Ea of the forward reaction and - ΔH, that is:
Ea = Ea - (-ΔH)
Ea = 10.7kJ/mol - (-199.8kJ/mol)
Ea = 210.5kJ/mole
![[OH^{-}] = 10^{-pOH}= 10^{-8.43}= 3.72*10^{-9} [OH^{-}]= 3.72*10^{-9}](https://tex.z-dn.net/?f=%5BOH%5E%7B-%7D%5D%20%3D%2010%5E%7B-pOH%7D%3D%2010%5E%7B-8.43%7D%3D%203.72%2A10%5E%7B-9%7D%0A%0A%20%5BOH%5E%7B-%7D%5D%3D%203.72%2A10%5E%7B-9%7D)