Dilution of a buffer solution with a small amount of water will ________ the ph of the solution.
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The question is incomplete,the complete question :
Calculate the molality of a 10.0% (by mass) aqueous solution of hydrochloric acid:
a) 0.274 m
b) 2.74 m
c) 3.05 m
d) 4.33 m
e) the density of the solution is needed to solve the problem
Answer:
The molality of a 10.0% (by mass) aqueous solution of hydrochloric acid is 3.05 mol/kg.
Explanation:
10.0% (by mass) aqueous solution of hydrochloric acid.
10 grams of HCl is present in 100 g of solution.
Mass of HCl = 10 g
Mass of solution = 100 g
Mass of solution = Mass of solute + Mass of water
Mass of water = 100 g - 10 g = 90 g
Moles of HCl =
Mass of water in kilograms = 0.090 kg
Molality =
The molality of a 10.0% (by mass) aqueous solution of hydrochloric acid is 3.05 mol/kg.
LiAlH₄ is used as strong reducing agent. The hydride produced acts as a nucleophile and attacks the electrophillic carbon of carbonyl group. In given example two reactions are observed.
Reaction 1:
In first step LiAlH₄ when treated with Ester produces corresponding Aldehyde and alcohol.
Reaction 2:
This aldehyde produced further reacts with LiAlH₄ to give a reduced product (Alcohols). In this case Butanol is produced.
The reaction schemes are shown as felow,
Reaction 1:
In first step LiAlH₄ when treated with Ester produces corresponding Aldehyde and alcohol.
Reaction 2:
This aldehyde produced further reacts with LiAlH₄ to give a reduced product (Alcohols). In this case Butanol is produced.
The reaction schemes are shown as felow,