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klio [65]
3 years ago
10

Which of the atoms below are least likely to violate the octet rule?

Chemistry
1 answer:
Levart [38]3 years ago
5 0

Answer:

F i think i pretty sure F!!!!!!!!

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At physiological ph, the ionized state of the carboxyl (cooh) group in the r group of aspartic acid is:
Wewaii [24]
Answer is: the ionized state of the carboxyl group is COO⁻.
Physiological pH is 7,4 and carboxyl group in the R group has pKa = 3,7. Since this pKa is lower than phys<span>iological pH of 7,4, carboxyl group (COOH) will lost proton, and because of that it will be deprotonated and will have negative charge.
</span>Aspartic acid<span> is an α-amino acid that is used in the biosynthesis of proteins.</span>
3 0
3 years ago
Why will a reaction occur between calcium oxalate and platinum?
olga2289 [7]

Answer:

Complex formation

Explanation:

At first sight, one may think that a reaction between calcium oxalate and platinum metal is impossible considering the relative positions of the two metals in the electrochemical series.

However, in solution, calcium oxalate dissociates into calcium and oxalate ions. When platinum is added to this solution, a complex is formed between the platinum ions and the oxalate ions. Hence a reaction occurs for this reason.

7 0
3 years ago
Read 2 more answers
The characteristic temperature at which a pure solid changes to a liquid is its ______ point.
Tasya [4]
It is known as the melting point
5 0
3 years ago
_AI + _HCI —&gt; _H2 + _AlCl3
SOVA2 [1]

Hey there!

Al + HCl → H₂ + AlCl₃

Balance Cl.

1 on the left, 3 on the right. Add a coefficient of 3 in front of HCl.

Al + 3HCl → H₂ + AlCl₃

Balance H.

3 on the left, 2 on the right. We have to start by multiplying everything else by 2.

2Al + 3HCl → 2H₂ + 2AlCl₃

Now we have 2 on the right and 4 on the left. Change the coefficient in front of HCl from 3 to 4.

2Al + 4HCl → 2H₂ + 2AlCl₃

Now, for Cl, we have 4 on the left and 6 on the right. Change the coefficient in front of HCl again from 4 to 6.

2Al + 6HCl → 2H₂ + 2AlCl₃

Now, our H is unbalanced again. 6 on the left, 4 on the right. Change the coefficient in front of H₂ from 2 to 3.

2Al + 6HCl → 3H₂ + 2AlCl₃  

Balance Al.

2 on the left, 2 on the right. Already balanced.

Here is our final balanced equation:

2Al + 6HCl → 3H₂ + 2AlCl₃  

Hope this helps!

7 0
3 years ago
Approximately 2.5 kg of carbon dioxide gas are produced for every liter of gasoline burned in an automobile gasoline engine. Cal
uranmaximum [27]
125 mile *1gallon/35 mi = 135/35 = (27/7) gallon gasoline 

27/7 gallon * 1 L/0.264 gallon = 14.6 L  gasoline

14.6 L gasoline * 2.5kg CO2/1L gasoline= 36.5 kg CO2

36.5 kg CO2 * 1lb/0.454 kg = 80.4 lb

Answer: 80.4 lb CO2

6 0
3 years ago
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