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irinina [24]
3 years ago
15

A cake manufacturer boxes Swiss chocolate and German chocolate cakes at one site. A box of Swiss chocolate cake contains 0.55 lb

of a sugar mixture and 0.45 lb of flour. A box of German chocolate cake contains 0.59 lb of the sugar mixture and 0.41 lb of flour. Each day at this site, the company has available 2,300 lb of the sugar mixture and 1,700 lb of flour. If all the ingrediates are utilized how many boxes of each type of cake can be made each day?
Mathematics
1 answer:
Kobotan [32]3 years ago
6 0

Answer:

2,500 German chocolate cake boxes.

1,500 Swiss chocolate cake boxes.

Step-by-step explanation:

Let 'S' be the number of Swiss chocolate cakes boxed and 'G' the number of German cholocate cakes boxed. If all of the available ingredients are used:

0.55*S +0.59*G = 2,300\\0.45*S+0.41*G = 1,700

Solving the linear system above:

(0.55 *S +0.59*G)- \frac{0.55}{0.45} (0.45*S+0.41*G)= 2,300-\frac{0.55}{0.45}*1,700*\\0.088888*G = 222.222\\G=2,500\\S =\frac{2,300-2,500*0.59}{0.55}\\S=1500

2,500 German chocolate cake boxes and 1,500 Swiss chocolate cake boxes can be made each day.

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3 years ago
a jar contains nickels and pennies. there are 56 coins in the jar in all. the total value of the coins is 1.52. how many pennies
nevsk [136]
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alrite...

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we know there are 56 coins in the jar, thus whatever "p" and "n" are,

p + n = 56

we also know, the total value of all pennies and nickels is one buck and 52 cents, or 1.52.. that's 152 pennies.

now, we know there are 5 pennies in one nickel, so in "n" nickels, there are 5*n pennies, or 5n, thus

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\bf \begin{cases}&#10;p+n=56\implies \boxed{n}=56-p\\&#10;p+5n=152\\&#10;----------\\&#10;p+5\left( \boxed{56-p} \right)=152&#10;\end{cases}

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