Answer : The pH of the resulting buffer is, 5.22
Explanation : Given,
First we have to calculate the moles of
and,
The balanced chemical reaction is:
Moles of HA left = 0.117 mol - 0.08 mol = 0.037 mol
Moles of = 0.08 mol
The expression used for the calculation of is,
Now put the value of in this expression, we get:
Now we have to calculate the pH of buffer.
Using Henderson Hesselbach equation :
Now put all the given values in this expression, we get:
Thus, the pH of the resulting buffer is, 5.22